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3 years ago

Trapezoid PSTK is isosceles. SK = 20, SH = 12, If ST = 1 4 HK, find HK, APTSK, m∠P, and PS. Find HK, Area of pstk, HK and PS

Mathematics

1 answer:

Vikentia [17]3 years ago

5 0

Answer:

HK = 16

Step-by-step explanation:

12^2+x^2=20^2

x = HK

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Neveah has created the function of f(x) = 2x+4/3 to represent the growth of her hair, where x represents the number of months si

Andre45 [30]

F(x)=2x+4/3

Replace f(x) by y:
y=2x+4/3

Solving for x:
y-4/3=2x+4/3-4/3

Subtracting the two terms on the left side of the equation:
(3y-4)/3=2x

Dividing both sides of the equation by 2:
[(3y-4)/3]/2=2x/2
[(3y-4)/3]*(1/2)=x
[(3y-4)*1]/[(3)*(2)]=x
(3y-4)/6=x
x=(3y-4)/6

Replace "x" by "f^(-1) (x)" (inverse function) and "y" by "x":
f^(-1) (x) = (3x-4)/6 Inverse function

Then, for x=6
f^(-1) (6) = [ 3(6)-4]/6
f^(-1) (6) = (18-4)/6
f^(-1) (6)= 14/6
f^(-1) (6) = 7/3

Her hair will have grown 6 after 7/3 = 2.33 months

3 0

3 years ago

The fitness club opens with 80 members each month the membership Increases by 15 members which equation represents the relations

creativ13 [48]

Answer:

y=15x+80

Step-by-step explanation:

where x is the monthly membership increase and y is the total amount of memberships

3 0

3 years ago

One more time!

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

3 years ago

4. Tell whether the systems have one solution,

hjlf

Answer:

x= 2,

,y = 5

Step-by-step explanation:

Solve by Substitution :

// Solve equation [1] for the variable y

[1] y = 5x - 5

// Plug this in for variable y in equation [2]

[2] -4x + 2•(5x-5) = 2

[2] 6x = 12

// Solve equation [2] for the variable x

[2] 6x = 12

[2] x = 2

// By now we know this much :

x = 2

y = 5x-5

// Use the x value to solve for y

y = 5(2)-5 = 5

Solution :

{x,y} = {2,5}

5 0

2 years ago

7(2а - 3) - 5a = -3<br><br> please show the work

Otrada [13]

Answer:

a = 2

Step-by-step explanation:

14a - 21 - 5a = -3

9a - 21 = -3

9a = -3 + 21

9a = 18

a = 2

4 0

3 years ago