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3 years ago

Factor the following polynomial 14x^2 - 35x

Mathematics

1 answer:

KonstantinChe [14]3 years ago

4 0

Answer:

The binomial 14 $x^{2}$ - 35x can be factored as 7x(2x+5)

Step-by-step explanation:

When factoring, you want to factor each constant or variable by their greatest common factor (or GCF). Since $14x^{2}$ and $35x$ has a greatest common factor of 7x, factor each term by 7x and you'll get $7x(2x+5)$ .

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Evaluate Combination (6,6)

andrew11 [14]

Answer:

$nCx = \frac{n!}{x! (n-x)!}$

On this case n =6 and x =6 we got:

$6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1$

Step-by-step explanation:

The utility for the combination formula is in order to find the number of ways to order a set of elements

For this case we want to find the following expression:

$6C6$

And the general formula for combination is given by:

$nCx = \frac{n!}{x! (n-x)!}$

On this case n =6 and x =6 we got:

$6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1$

8 0

3 years ago

Jill''s family divided a while lasagna into 10 pieces of equal size. they ate 2/5 of the lasagna. Which fraction represents the

barxatty [35]

There are 6/10 left over. 6/10 reduces to 3/5.

7 0

3 years ago

Which statement makes the open sentence true 2x-7= -1

oee [108]

Answer:

Step-by-step explanation:

if you plug in 3 for x, it becomes 2(3)-7=-1

then 6-7=-1

-1=-1

6 0

3 years ago

An adult ticket to a museum costs 3$ more than a children’s ticket. When 200 adult tickets and 100 children tickets are sold, th

antiseptic1488 [7]

The cost of children’s ticket is $ 5

<h3><u>Solution:</u></h3>

Let "c" be the cost of one children ticket

Let "a" be the cost of one adult ticket

Given that adult ticket to a museum costs 3$ more than a children’s ticket

<em>Cost of one adult ticket = 3 + cost of one children ticket</em>

a = 3 + c ------ eqn 1

<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>

200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

$200 \times a + 100 \times c = 2100$

200a + 100c = 2100 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>

Substitute eqn 1 in eqn 2

200(3 + c) + 100c = 2100

600 + 200c + 100c = 2100

600 + 300c = 2100

300c = 1500

Thus the cost of children’s ticket is $ 5

6 0

3 years ago

Each month, an American household generates an average of 28 pounds of newspaper for garbage or recycling. Assume the standard d

Annette [7]

a) For x = 27:

z = 27-28/2 = -0.5

For x = 31:

z = 31-38/2 = 1.5

From the normal distribution table, P(27 < x < 31) = P(-0.5 < z < 1.5) = P(z < 1.5) - P(z < -0.5) = 0.9332 - 0.3085 = 62.47%

b) For x > 30.2:

z = 30.2-28/2 = 1.1

From the normal distribution table, P(x > 30.2) = P(z > 1.1) = 1 - P(z > 1.1) = 1 - 0.8643 = 13.57%

4 0

2 years ago