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Phantasy [73]
3 years ago
8

Can you guys help me??? 6 = -5 + u. What is u???

Mathematics
1 answer:
ale4655 [162]3 years ago
3 0

Work is provided in the image attached.

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(-1)x^{2} 299 cual es el resultado y los pasos?
GuDViN [60]
Answer: 299x^2 I think I hope we help you
7 0
3 years ago
1.What is the area of the circles<br><br> What is the area of the shaded region?
Rama09 [41]

Answer:

47.32 in^2

Step-by-step explanation:

Area rectangle = 21cm * 10.5cm = 220.5 cm^2

Area circle = pi*r^2

= Pi * 5.25^2

=( 86.59 in^2 )*2

= 173.18 in^2

Shaded region. 220.5 - 173.18 = 47.32 in^2

6 0
3 years ago
A hose fills a hot tub at a rate of 4.74 gallons per minute. How many hours will it take to fill a 294​-gallon hot​ tub?
saveliy_v [14]
So the hose can do 4.74 gallons in 1 minute, how many minutes will it take for 294 gallons?

\bf \begin{array}{ccll}&#10;gallons&minutes\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;4.74&1\\&#10;294&m&#10;\end{array}\implies \cfrac{4.74}{294}=\cfrac{1}{m}\implies m=\cfrac{294\cdot 1}{4.74}&#10;\\\\\\&#10;m\approx 62.0253164556962

and since there are 60 minutes in 1 hour, how many hours is that?

\bf \begin{array}{ccll}&#10;hours&minutes\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;1&60\\&#10;h&62.0253164556962&#10;\end{array}\implies \cfrac{1}{h}=\cfrac{60}{62.0253164556962}&#10;\\\\\\&#10;\cfrac{1\cdot 62.0253164556962}{60}\approx h
7 0
3 years ago
Help plz and teach me how to answer
horrorfan [7]
Helen subtracted 17 from the right side of the equation when she should have added 17. Adding 17 to both sides would have gotten x/y by itself.

The answer is 'Helen should have added 17 to both sides of the equation'.
4 0
3 years ago
Read 2 more answers
As part of a study of the association between smoking and risk of squamous cell carcinoma, a logistic regression model was estim
AlekseyPX

Answer:

0.44

Step-by-step explanation:

Given the estimated logistic regression model on risk of having squamous cell carcinoma

-4.84 + 4.6*(SMOKER)

SMOKER = 0 (non-smoker) ; 1 (SMOKER)

What is the predicted probability of a smoker having squamous cell carcinoma?

exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))

SMOKER = 1

exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)

exp^(-0.24) / (1 + exp^(-0.24))

0.7866278 / 1.7866278

= 0.4402863

= 0.44

3 0
3 years ago
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