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borishaifa [10]
2 years ago
7

Y = x-8 y = -2x +1 i need it in graph form

Mathematics
1 answer:
umka2103 [35]2 years ago
6 0
Here is the graph for those equations

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A bowl contained 250 skittles. The result of 25 fruit-flavored candies pulled at random is given below. Based on this informatio
Anastaziya [24]

OK so you have 250 skittles. But you only pull out 25. You pull out 5 red skittles, 7 yellow skittles,8 orange skittles,2 green skittles and 3 purple skittles. So how many red skittles are in the whole box. The way i would look at it is theres 5 red skittles in every 25 skittles. So whats 250 divided by 25 that would be 10. So you can imagine you have 10 groups of skittles. In each group theres 5 skittles. So all together there would be 50 red skittles. Sooo based on the infromation there would be 50 red skittles expected in the box. I hope this helped pls mark me as brainliest!!

7 0
2 years ago
For a one-tailed test with a = .05 and a sample of n = 9, the critical value for the t statistic is t = 1.860.
ahrayia [7]
I think its B. False if im wrong sorry hope this helped tho :p
6 0
3 years ago
Create and solve a linear equation that represents the model, where circles and a square are shown evenly balanced on a balance
Maslowich

A linear equation that represents the model is: x + 6 = 10; x = 4

<h3>How to solve linear equations?</h3>

Let us first define the variables based on the attached image of the ball balance:

Let x = number of balls that contains the square.

On the left side, we have; square + 6 balls

On the right side, we have; 10 balls

To balance this, we have;

x + 6 = 10

x = 10-6

x = 4

Thus, a linear equation that represents the model is:

x + 6 = 10; x = 4

Read more about Linear equations at; brainly.com/question/9406333

#SPJ1

3 0
2 years ago
Find the limit as x approaches infinity of y=arccos(1+x21+2x2)y=arccos((1+x^2)/(1+2x^2))?
Katyanochek1 [597]
If x approach infinity then (x² + 1)/(2x² +1) = 1/2 then lim as x  approach infinity
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6 0
3 years ago
Need help with this....
Yakvenalex [24]

Answer:

\boxed{\dfrac{f(a+h)-f(a)}{h}=-3a^2-3ah-h^2}

Step-by-step explanation:

f(x)=-x^3+2\\\\\dfrac{f(a+h)-f(a)}{h}\\\\f(a+h)\to\text{substitute x = a + h}\\f(a)\to\text{substitute x = a}\\\\\dfrac{f(a+h)-f(a)}{h}=\dfrac{-(a+h)^3+2-(-a^3+2)}{h}\\\\\text{use}\ (x+y)^3=x^3+3x^2y+3xy^2+y^3\\\\=\dfrac{-(a^3+3a^2h+3ah^2+h^3)+2-(-a^3)-2}{h}\\\\=\dfrac{-a^3-3a^2h-3ah^2-h^3+2+a^3-2}{h}\\\\\text{combine like terms}

=\dfrac{(-a^3+a^3)-3a^2h-3ah^2-h^3+(2-2)}{h}\\\\=\dfrac{-3a^2h-3ah^2-h^3}{h}\\\\=\dfrac{h(-3a^2-3ah-h^2)}{h}\\\\=-3a^2-3ah-h^2

6 0
2 years ago
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