Answer:
7m^5 - 3m^3 - 3
Step-by-step explanation:
first multiply the outside numbers by both the numbers in the ()
10xg=10g 10x5=50 2xg=2g 2x9=18
then combine like terms
10g+50=2g+18
8g=32
then divide
g=4
The answer will be as shown in the pic 15x^(2) +35x
The quantity you want is the area under the standard normal curve (with mean 100 and std dev 15) between 110 and 120.
According to my TI-83 calculator,
normalcdf(110,120, 100, 15) = 0.16, or 16%.
Answer:
2400KM hope this helps sorry if im
wrong
im not good with ratios and unit conversion
