If it takes 20 minute to get to the airport, and he wants to be there an hour and 5 minutes before his flight leaves, we have to subtract the time he leaves (9:50) by 1 hour and 5.
9:50 - 1 hour and 5 minutes.
9:50 - 65 minutes.
9:50 - 65 = 8:45.
Which means he must be at the airport at 8:45.
BUT,
The question is asking for the latest time that Quincy can LEAVE for the airport, which means it's 8:45 - 20 minutes, since it takes 20 minutes to get to the airport:
8:45 - 20 = 8:25
The answer is B: <span> a^12/b^6
Proof:
Simplify the following:
(a^4/b^2)^3
Multiply each exponent in a^4/b^2 by 3:
(a^(3×4))/((b^2)^3)
3×4 = 12:
a^12/(b^2)^3
Multiply exponents. (b^2)^3 = b^(2×3):
a^12/b^(2×3)
2×3 = 6:
Answer: a^12/b^6</span>
Yes the problem is true and 56 is a solution
Answer:
the line pls?
Step-by-step explanation:
