Decimals between 9.4 to 10.5 with an interval of 0.1 between each pair of decimals

1 answer:

8 0

<span>Decimals between 9.4 to 10.5 with an interval of 0.1 between each pair of decimals are {9.5, 9.6, 9.7, 9.8, 9.9, 10.0, 10.1, 10.2, 10.3, 10.4}</span>

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Given the following information about glucose levels (in milligrams of glucose per 100 milliliters of blood.) ( from 9.5)

Svetllana [295]

Answer:

A. 16.385

B. 9.532

C. (16.358)^2 is different from (9.532)^2

a. sigma squared of non pregnant women is GREATER THAN sigma squared of pregnant women

Step-by-step explanation:

<h3>A and B. Standard Deviation 's' of both columns:</h3>

The formula for the standard deviation is:

s = √(∑(x - μ)²/(n))

where,

∑ = is the sum function

x = a number from the set

μ = mean of the set

n = is the amount of the numbers in the set.

the column of non-pregnant women is

[73, 61, 104, 75, 85, 65, 62, 98, 92, 106]

first find the mean of this set:

mean = μ = (sum of all the numbers)/(amount of numbers)

μ = [73 + 61 + 104 +75 + 85 + 65 + 62 + 98 + 92 + 106]/(10)

μ = 821/10

μ = 82.1

similarly, for pregnant women the mean is

μ = 80.125

now, to find the standard deviation 's', first we need to find the variance 's²'. So, what you have to do is subtract each value in the column with the mean 'μ' and square the result.

for non-pregnant you will get:

[ 82.81, 445.21, 479.61, 50.41, 8.41, 292.41, 404.01, 252.81, 98.01, 571.21]

for pregnant you will get:

[ 66.015, 15.015, 97.515, 221.265, 199.51, 102.515, 1.265, 23.76]

finally just sum all the numbers of a column and divide with the amount of numbers in that column (remember that col1 has 10 numbers and col2 has 8 numbers). And you will get your variance for both pregnant and non-pregnant women:

for non-pregnant = 2684.89/10

non-pregnant = 268.4 (this is the variance and it is denoted by s²)

for standard deviation 's', just take the square root of the variance

$\sqrt{268.4}$ = 16.385.