We can solve this problem by seeing at which part both of the parts of the graphs of the function are discontinued. Both of the parts of the graph of the function are discontinued at -2, so we will have to find a function that has a value that is undefined for x = -2. We can do this using the denominator of the fraction that's in each of the functions. The function where x = -2 will cause it to be undefined is the third one, so the answer to this question is C.,
f (x) = +5.
Option C. all real numbers greater than 0 is the correct answer
Further explanation:
Domain is the set of all inputs on which the function is defined or real.
The given function is:
As the function involves a square root, we have to avoid negative numbers.
- All positive real numbers will produce defined output so the positive real numbers will be included in the domain.
- If we look at negative real numbers, we will be taking square root of a negative number which will not result in a real number
So the domain will only include positive real numbers.
Hence, Option C. all real numbers greater than 0 is the correct answer.
Keywords: Domain, Domain of radical functions
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F(-1) = 12 - 5(-1)
f(-1) = 12 + 5
Solution: f(-1) = 17
Answ
its a just did this
Step-by-step explanation:
3x^2+21x+6=3(3x^2+7x+2)=3(3x^2+6x+x+2)=3[3x(x+2)+(x+2)]=3(3x+1)(x+2)