Answer:
8
Explanation:
u can find it on ur chemistry book
The molarity of the potassium acetate solution given the data is 1.584 M
<h3>What is molarity? </h3>
This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
<h3>How to determine the mole of CH₃COOK</h3>
- Mass of CH₃COOK = 19.4 g
- Molar mass of CH₃COOK = 98 g/mol
- Mole of CH₃COOK =?
Mole = mass / molar mass
Mole of CH₃COOK = 19.4 / 98
Mole of CH₃COOK = 0.198 mole
<h3>How to determine the molarity of CH₃COOK</h3>
- Mole of CH₃COOK = 0.198 mole
- Volume = 125 mL = 125 / 1000 = 0.125 L
- Molarity of CH₃COOK = ?
Molarity = mole / Volume
Molarity of CH₃COOK = 0.198 / 0.125
Molarity of CH₃COOK = 1.584 M
Learn more about molarity:
brainly.com/question/15370276
#SPJ4
There will be 7.5 g of Be-11 remaining after 28 s.
If 14 s = 1 half-life, 28 s = 2 half-lives.
After the first half-life, ½ of the Be-11 (15 g) will disappear, and 15 g will remain.
After the second half-life, ½ of the 15 g (7.5 g) will disappear, and 7.5 g will remain.
In symbols,
<em>N</em> = <em>N</em>₀(½)^<em>n</em>
where
<em>n</em> = the number of half-lives
<em>N</em>₀ = the original amount
<em>N</em> = the amount remaining after <em>n</em> half-lives
Answer:
0.933 L
Explanation:
Since the pressure is the same, we use the equation ![\frac{V_{1}}{T_{1} } = \frac{V_{2} }{T_{2} }](https://tex.z-dn.net/?f=%5Cfrac%7BV_%7B1%7D%7D%7BT_%7B1%7D%20%7D%20%3D%20%5Cfrac%7BV_%7B2%7D%20%7D%7BT_%7B2%7D%20%7D)
V = Volume
T = Temperature
Since we are given the temperature in Celsius, we need to convert it to Kelvin by adding 273:
-55.0 + 273 = 218
40.0 + 273 = 313
![\frac{0.650}{218} = \frac{x}{313}](https://tex.z-dn.net/?f=%5Cfrac%7B0.650%7D%7B218%7D%20%3D%20%5Cfrac%7Bx%7D%7B313%7D)
![0.933 = x](https://tex.z-dn.net/?f=0.933%20%3D%20x)
The gas will occupy a volume of 0.933 L.
(Side note - If the temperature increases, the gas will want to expand, leading to a higher volume.)