Answer:
9.01 grams
Explanation:
~18.02 grams are in 1 mole of water so you'd divide that in half to get 9.01 grams.
Q=hc A (Ts-Ta)
q = heat transfered per unit time
A= heat transfer area of the surface
hc= convective heat transfer coefficient of the process
Ts= temperature of the surface
Ta= temperature of the air
This problem is providing us with the mass of propane, its enthalpy of combustion, and the initial and final temperature of water that can be heated from the burning of this fuel. At the end, the result turns out to be 42.27 L.
<h3>Combustion:</h3>
In chemistry, combustion reactions are based on the burning of fuels by using oxygen and producing both carbon dioxide and water. For propane, we will have:

Hence, we can calculate the heat released from this reaction by using the mass, which has to be converted to moles, and the given enthalpy of combustion:

<h3>Calorimetry:</h3>
In chemistry, we can analyze the mass-specific heat-temperature-heat relationship via the most general heat equation:

Thus, since Q was obtained from the previous problem, but the sign change because the released heat is now absorbed by the water, one can calculate the mass of water that rises from 20.0°C to 100.0°C with this heat:

Finally, we convert it to liters as required:

Learn more about calorimetry: brainly.com/question/1407669