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snow_tiger [21]
3 years ago
14

Consider the function f(x) = 6 sine (x minus StartFraction pi Over 8 EndFraction) + 8. What transformation results in g(x)6 sine

(x minus StartFraction 7 pi Over 16 EndFraction) + 1?
Translate StartFraction 5 pi Over 16 EndFraction units left and 7 units up.
Translate StartFraction 5 pi Over 16 EndFraction units right and 7 units up.
Translate StartFraction 5 pi Over 16 EndFraction units left and 7 units down.
Translate StartFraction 5 pi Over 16 EndFraction units right and 7 units down.
Mathematics
2 answers:
kkurt [141]3 years ago
7 0

Answer:

C

Step-by-step explanation:

edge correct

Naily [24]3 years ago
3 0

Answer:

C

Step-by-step explanation:

EDG 2020

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madreJ [45]

Answer:

y = 3x - 17

Step-by-step explanation:

Parallel lines have the same slope so the equation would be y = 3x + b

plugging in the points you get -2 = 3(5) + b

this is -17 = b

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Mike observed that 75% of the students of a school liked skating. If 35 students of the school did not like skating, the number
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If 75% liked skating, then 25% did not
so 25% of what is 35
0.25x = 35
x = 35/0.25
x = 140...so there is a total of 140 students

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3 years ago
Find the equation of the line with m=6 and b = -7. Write the equation in slope intercept form.​
Harman [31]

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Step-by-step explanation:

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4 0
3 years ago
the music hall has 20 boxes on thurs 2/5 were occupied, on friday 2/4 were occupied and o saturday 8/10 were occupied. Using sym
NikAS [45]
<span><span>1.       </span>The music hall has 20 boxes :
=> on thurs 2/5 were occupied
=> on friday 2/4 were occupied
=> and on saturday 8/10 were occupied.
Let’s find out which day has the most occupied space of the music hall.
2/5 + 2/4 + 8/10 = 6/20 + 7/20 + 10/20
Thurs 2/5 were occupied
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=> 20 * 0.3 = 6 boxes
Friday 2/4 were occupied
=> 7/20 = 0.35
=> 20 * 0.35 = 7 boxes
Saturday 8/10 were occupied.
=> 10/20 = 0.5
=> 20 * .5 = 10 boxes
Thus, during Saturday has the most number of occupied boxes.</span>



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