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Alik [6]
3 years ago
10

Which statement explains the difference between a point and a vertex please fast

Mathematics
2 answers:
dlinn [17]3 years ago
8 0

The difference between point and the vertx is that a vertex can be used to create different geometric shapes and a point is always part of the shape.

Step-by-step explanation:

Though Vertex and Point sound similar, they are different in many crude aspects. Vertex is defined as the meeting point of two sides, lines or any extended parts. The point, in turn, denotes the singular identity of a place.

Hence vertex can be used to draw any geometrical pattern. It can be done by extending or protruding the given body parts which would result in a new geometrical figure.

Points would constitute every part of that geometrical surface that we wish to identify.

Mashutka [201]3 years ago
4 0

Answer:

A vertex contains an infinite number of points, and a point does not have width or depth.

Step-by-step explanation:

Its kinda late but i think this is the right answer tho

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X ^ 2 + 4x - 7 = 0<br><br> Solve using the Quadratic Formula
aalyn [17]

There's a special case of the quadratic formula called the Shakespeare Quadratic Formula (2b or -2b) that applies when the linear coefficient is even.

x^2-2Bx + C \textrm{ has zeros }x = B \pm\sqrt{B^2 - C}

If you're planning on solving a lot of quadratic equations quickly, it's good to know.

Here we have

x^2 + 4x - 7 = 0

so

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8 0
3 years ago
Help with all please
seropon [69]

a) First, draw a graph. The x axis should be numbered: 0, 1, 2, 3, 4, 5, 6, 7, 8. Each number is the last digit of the year. For each year, there is one average score that has to be plotted. Number the y axis of the graph from 0-600, by increments of 50, or something around there. Now, with each year (each x value) place the dot as high as the average score. Repeat with all years. DO NOT draw a line to connect them. A scatter plot is a bunch of points that are not connected.

b) Use the form (y2-y1)/(x2-x1) where (x1,y1) (x2,y2) are any two points from 2001-2006. It does not matter which points, pick any, and assign each of the numbers x1,y1 and x2,y2. Plug it in to the equation, and simplify. This is your slope, also called m. Now plug m into the equation y-y1=m(x-x1) where y1 and x1 are the x and y coordinates of any point from 2001 to 2006. x and y dont have values themselves, they stay there. Now distribute the m into the parenthesis, add y1 to both sides (to cancel it out on the left), and you should be left with the same equation, but now in y=mx+b form. B is where the line crosses the y axis, so put a point on the vertical axis where b is. M is your slope, so every time you go to the right one number, go up M numbers. Draw another point. Repeat this until you can connect these new dots into a line. This line should be on the same graph as your other points, but might not touch all of the scatter plot points. That's still okay, just leave it as is.

c) Find the point where x=6 (meaning the year is 2006) on your line. Find the average test score for that year by seeing where the point lines up along the y axis (draw a straight line from the point to the left to see, if you have to). Take that number and add 1m (the m is the number you used in step B) to it. This predicts what the average score might be after 1 (that's why the 1 is there) year. This is a predicted value, and might not be perfectly correct!! Write/record how close this new, predicted, score is to the actual number, 515, which can be found on the scatter plot.

d) repeat step C exactly as before (still use the year 2006) , but add 4m instead of 1m, to get the predicted score 4 years after 2006 (2010), instead of 1 year after (2007).

I hope I have been of some help! Best of luck!!! :)

3 0
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Rus_ich [418]
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Ghella [55]

Answer:

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cos23° = \frac{adjacent}{hypotenuse} = \frac{23.4}{x} ( multiply both sides by x )

x × cos23° = 23.4 ( divide both sides by cos23° )

x = \frac{23.4}{cos23} ≈ 25. 4 Km ( to the nearest tenth )

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attashe74 [19]
Option A would run parallel because they have the same slope.
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