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igor_vitrenko [27]
4 years ago
9

You have 18 skittles. You want to eat 5/6 of them and save 1/3 of them for later. Can you do this?

Mathematics
1 answer:
sertanlavr [38]4 years ago
6 0

Answer: yes because you can save 1/3 of the skittles from the 1/6 of the skittles you didnt eat earlier but idk where the rest of the skittles that you are not saving and didnt eat would go.

Step-by-step explanation: hope this helps :!.

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Simplify the following expression. −3√84x3
prisoha [69]

Answer:

-18root7

Step-by-step explanation:

-3root 84*3

-3root4*7*3*3

-3(2*3)root7

-18root7

8 0
4 years ago
For about $1 billion in new space shuttle expenditures, NASA has proposed to install new heat pumps, power heads, heat exchanger
11111nata11111 [884]

Answer:

The probability of one or more catastrophes in:

(1) Two mission is 0.0166.

(2) Five mission is 0.0410.

(3) Ten mission is 0.0803.

(4) Fifty mission is 0.3419.

Step-by-step explanation:

Let <em>X</em> = number of catastrophes in the missions.

The probability of a catastrophe in a mission is, P (X) = p=\frac{1}{120}.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X </em>is:

P(X=x)={n\choose x}\frac{1}{120}^{x}(1-\frac{1}{120})^{n-x};\x=0,1,2,3...

In this case we need to compute the probability of 1 or more than 1 catastrophes in <em>n</em> missions.

Then the value of P (X ≥ 1) is:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-{n\choose 0}\frac{1}{120}^{0}(1-\frac{1}{120})^{n-0}\\=1-(1\times1\times(1-\frac{1}{120})^{n-0})\\=1-(1-\frac{1}{120})^{n-0}

(1)

Compute the compute the probability of 1 or more than 1 catastrophes in 2 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{2-0}=1-0.9834=0.0166

(2)

Compute the compute the probability of 1 or more than 1 catastrophes in 5 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{5-0}=1-0.9590=0.0410

(3)

Compute the compute the probability of 1 or more than 1 catastrophes in 10 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{10-0}=1-0.9197=0.0803

(4)

Compute the compute the probability of 1 or more than 1 catastrophes in 50 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{50-0}=1-0.6581=0.3419

6 0
3 years ago
!!!!!PLEASE HELP ME RIGHT NOW I NEED TO TURN THIS IN, IN 10 MINUTES HELP HELP PLEASE!!!!!!write a multiplication equation that r
SpyIntel [72]
I think the answers 6x 2/3
7 0
3 years ago
The camp cook made 1 1/2 pots of chicken soup. Each serving of soup is 1/4 of a pot. How many servings of chicken soup did the c
allochka39001 [22]

The camp cook made 6 servings of chicken soup

Number of pots of soup=1 1/2

one serving of soup is 1/4 of a pot.

number of servings of pot of soup=Number of pots of soup/ serving of soup

number of servings of pot of soup=1 1/2 /1/4

number of servings of pot of soup=3/2 x 4/1=6 servings of chicken soup

See similar question here:  brainly.com/question/17745626

4 0
3 years ago
PLEASE HELP! I WILL MARK BRAINLIEST IF U ANSWER WITHIN THE NEXT 2 MINS!
Anna35 [415]

Answer:

-1\4 is the correct answer

6 0
3 years ago
Read 2 more answers
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