Answer:
hope it's helpful for you
Answer:
The equation that represented by the line is y = -x + 2
Step-by-step explanation:
The slope-intercept form of the linear equation is y = m x + b, where
- m is the slope of the line
- b is the y-intercept (value y at x = 0)
The rule of the slope is m =
, where
- (x1, y1) and (x2, y2) are two points on the line
<em>From the given figure </em>
∵ The line passes through points (2, 0) and (0, 2)
∴ x1 = 2 and y1 = 0
∴ x2 = 0 and y2 = 2
→ Substitute them in the rule of the slope to find it
∵ m = 
∴ m = -1
→ Substitute it in the form of the equation above
∵ y = -1(x) + b
∴ y = -x + b
∵ b is value y at x = 0
∵ At x = 0, y = 2
∴ b = 2
→ Substitute it in the equation above
∴ y = -x + 2
∴ The equation that represented by the line is y = -x + 2
Well you'd use the distance formula for each pair of points:
d = sq.root of((x2 - x1)^2 + (y2-y1)^2)
(1) For the points (-5,6) and (-5,-2):
d = sq.root of((-5-(-5))^2 + (-2-6)^2)
= sq.root of (0 + 64)
= 8
(2) For the points (-5,-2) and (1,-2):
d = sq.root of((1-(-5))^2 + (-2-(-2))^2)
= sq.root of (36 + 0)
= 6
(3) For the points (1,-2) and (-5,6):
d = sq.root of((-5-1)^2 + (6-(-2))^2)
= sq.root of(36 + 64)
= sq.root of(100)
= 10
Therefor the length of the longest side is 10 units
Answer:
The answer to the question is -16.
What's the shape??????????????????????????