1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
fgiga [73]
3 years ago
14

Give the domain and range of each relation

Mathematics
1 answer:
adelina 88 [10]3 years ago
7 0
Domain is -2 and 4 range is 4 and 2
You might be interested in
A pharmacist has an 18% alcohol solution and a 40% alcohol solution. How much of each should he mix together to make 10 liters o
ladessa [460]
X = amount of the 18% solution

y = amount of the 40% solution

we know the 18% solution has only 18% of alcohol, the rest is maybe water or something, now, how many liters is 18%?  well, 18% of anything is just (18/100) * anything, so, 18% of x is just (18/100) *x or 0.18x, and that's how many liters are there.

likewise, how many liters are there in the 40% solution?  well, (40/100) * y, or 0.4y, that many.

we know the mixture has to yield 10 liters at 20% alcohol, how many liters of only alcohol is that?  well, (20/100) * 10, or 2 liters.

\bf \begin{array}{lccclll}
&\stackrel{liters}{amount}&\stackrel{alcohol~\%}{quantity}&\stackrel{liters}{alcohol}\\
&------&------&------\\
\textit{18\% solution}&x&0.18&0.18x\\
\textit{40\% solution}&y&0.40&0.4y\\
------&------&------&------\\
mixture&10&0.20&2
\end{array}

\bf \begin{cases}
x+y=10\implies \boxed{y}=10-x\\
0.18x+0.4y=2\\
----------\\
0.18x+0.4\left( \boxed{10-x} \right)=2
\end{cases}
\\\\\\
0.18x-0.4x+4=2\implies -0.22x=-2
\\\\\\
x=\cfrac{-2}{-0.22}\implies x=\cfrac{100}{11}\implies x=9\frac{1}{11}

how much of the 40% solution?  well y = 10 - x
3 0
4 years ago
The figure shows △ABC . BD is the angle bisector of ∠ABC .
Misha Larkins [42]
From angle bisector theorem, we know that:

\dfrac{|AD|}{|DC|}=\dfrac{|BA|}{|BC|}\\\\\\\dfrac{|AD|}{|DC|}=\dfrac{8}{10}=\dfrac{4}{5}

Moreover:

|AD|+|DC|=6

so:

|DC|=6-|AD|

and

\dfrac{|AD|}{|DC|}=\dfrac{4}{5}\\\\\\\dfrac{|AD|}{6-|AD|}=\dfrac{4}{5}\qquad\qquad\text{cross multiplying}\\\\\\ 5\cdot|AD|=4\cdot\big(6-|AD|\big)\\\\5\cdot|AD|=24-4\cdot|AD|\\\\5\cdot|AD|+4\cdot|AD|=24\\\\9\cdot|AD|=24\qquad|:9\\\\\\|AD|=\dfrac{24}{9}=\boxed{\dfrac{8}{3}}

3 0
3 years ago
Read 2 more answers
For what value of k does the equation have no solution? kx - 4 = 5x + 8
baherus [9]

Answer:

Your answer is: k = 5+12/x

Isolate the variable by dividing each side by factors that don't contain the variable.

Step-by-step explanation:

Hope this helped : )

7 0
3 years ago
Megan earns $20.00 by walking dogs. She uses all of her earnings to buy a shirt for $12.85 and some stickers for $0.65 each. How
Leya [2.2K]
The answer is B: 11.

To solve it, you need to solve the equation: 20.00=12.85+0.65x
4 0
4 years ago
WHAT IS THE SQUARE ROOT OF 400
snow_tiger [21]
The square root of 400 is 20
7 0
3 years ago
Read 2 more answers
Other questions:
  • Im doing a test review and I have no idea how to do this​
    14·1 answer
  • These are linear openings that form in materials to relieve stress
    7·1 answer
  • How do i add and subtract polynomials?<br>(4v-6v)-(v-5v^3)+(5v^3+4)
    11·1 answer
  • What is the mean of the set of numbers, {–11, 22, –2, –3}? A. –6.5 B. –1.5 C. 1.5 D. 6.5
    8·2 answers
  • A shopper bought 15 apples and 5 oranges. Which statement describes the ratio of apples to
    7·1 answer
  • 24 = 12а - 24 hurrrrryyyyy pleaseeee
    14·2 answers
  • A shark was caught whose tail weighed 200 pounds. The head of the shark weighed as much as its tail plus half its body. It’s bod
    9·2 answers
  • To map △PQR onto △STU, there must be a factor k that reduces △PQR.
    14·1 answer
  • Find the greatest common factor of 15x^6 and 33x^4y^5
    8·2 answers
  • Karen walked tKaren walked 3 miles in 48 minutes popped walked 1 mile further than Karen it took Bob one hour and five minutes t
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!