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3 years ago

Give the domain and range of each relation

Mathematics

1 answer:

adelina 88 [10]3 years ago

7 0

Domain is -2 and 4 range is 4 and 2

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The quadratic function d= -4x+1,100 models a snowboarder's distance, in feet, from the bottom of a hill x seconds after the snow

Fynjy0 [20]

Answer:

16 seconds (Approximately)

Step-by-step explanation:

Given:

The function that gives the distance of snowboarder from the bottom of hill with time 'x' is:

$d=-4x^2+1100$

Final position of the snowboarder is $d=100\ ft$

Now, plugging in 100 for 'd' and solving for 'x', we get:

$100=-4x^2+1100$

Adding -1100 both sides, we get:

$100-1100=-4x^2+1100-1100\\-1000=-4x^2$

Dividing both sides by -4, we get:

$\frac{4x^2}{4}=\frac{1000}{4}\\x^2=250$

Taking square root and neglecting the negative root as time can't be negative. So,

$\sqrt{x^2}=\sqrt{250}\\x=5\sqrt{10}=15.8\ s\approx 16\ s$

Therefore, after 16 seconds, the snowboarder will be at a distance of 100 ft from bottom of hill.

7 0

3 years ago

Help, I'm doing rhis problem and need help checking if I'm right.

umka2103 [35]

To me it looks like your right

7 0

3 years ago

-0.5,1.25,-1/3,0.5,-5/3 ordered from least to greatest

vampirchik [111]

Answer:

Step-by-step explanation:

-5/3,-0.5,-1/3,0.5,1.25

8 0

3 years ago

How is Solving for speed similar to solving for time? They both require that two numbers be added. They both require that two nu

sweet [91]

Answer:

They both involve writing a rate.

Step-by-step explanation:

EDGENUITY ANSWER

7 0

3 years ago

Read 2 more answers

Nadia is investigating rotations about the center of regular polygons that carry the regular polygon onto itself. She claims tha

GalinKa [24]

Answer:

$\theta_1 \ n\ \theta_2 = 120, 240$

Step-by-step explanation:

The question is incomplete, as the angles of rotation are not stated.

However, I will list the angles less than 360 degrees that will carry the hexagon and the nonagon onto itself

We have:

$Nonagon = 9\ sides$

$Hexagon = 6\ sides$

Divide 360 degrees by the number of sides in each angle, then find the multiples.

<u>Nonagon</u>

$\theta = \frac{360}{9} =40$

List the multiples of 40

$\theta_1 = 40, 80, 120, 160, 200, 240, 280, 320$

<u>Hexagon</u>

$\theta = \frac{360}{6} =60$

List the multiples of 60

$\theta_2 = 60, 120, 180, 240, 300$

List out the common angles

$\theta_1 = 40, 80, 120, 160, 200, 240, 280, 320$

$\theta_2 = 60, 120, 180, 240, 300$

$\theta_1 \ n\ \theta_2 = 120, 240$

This means that, only a rotation of $120, 240$ will lift both shapes onto themselves, when applied to both shapes.

The other angles will only work on one of the shapes, but not both at the same time.

7 0

3 years ago