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love history [14]
3 years ago
11

Nadia is investigating rotations about the center of regular polygons that carry the regular polygon onto itself. She claims tha

t there are rotations about the center that will carry both a regular hexagon and a regular nonagon (9-sided polygon) onto itself. Determine whether each angle of rotation below can be used to support Nadia's claim. Select Yes or No for each angle of rotation
Mathematics
1 answer:
GalinKa [24]3 years ago
7 0

Answer:

\theta_1 \ n\ \theta_2 = 120, 240

Step-by-step explanation:

The question is incomplete, as the angles of rotation are not stated.

However, I will list the angles less than 360 degrees that will carry the hexagon and the nonagon onto itself

We have:

Nonagon = 9\ sides

Hexagon = 6\ sides

Divide 360 degrees by the number of sides in each angle, then find the multiples.

<u>Nonagon</u>

\theta = \frac{360}{9} =40

List the multiples of 40

\theta_1 = 40, 80, 120, 160, 200, 240, 280, 320

<u>Hexagon</u>

\theta = \frac{360}{6} =60

List the multiples of 60

\theta_2 = 60, 120, 180, 240, 300

List out the common angles

\theta_1 = 40, 80, 120, 160, 200, 240, 280, 320

\theta_2 = 60, 120, 180, 240, 300

\theta_1 \ n\ \theta_2 = 120, 240

This means that, only a rotation of 120, 240 will lift both shapes onto themselves, when applied to both shapes.

The other angles will only work on one of the shapes, but not both at the same time.

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on monday mrs jones spent 32 dollars on 4 books. on tuesday she spent $16 on more books.each book cost the same amount. how many
Gala2k [10]
She bought 6 books in all because if you divide the whole number of all the books in all which is $32 divide that by 4 so..

32 
÷4=8

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3 years ago
Square root of 20<br> O Between 5 and 6<br> O Between 4 and 5<br> O Between 3 and 4<br> 0 4
marta [7]

Answer:

B. It is between 4 and 5

Step-by-step explanation:

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7 0
3 years ago
How do I simplify these expressions?<br> 5(x+8)+3<br> 3.6x-7-5.1x<br> 4+8x+2.2-10x
Aleks04 [339]

Answer:

1. 5x +43

2. -1.5x - 7

3. 6.2 - 2x

Step-by-step explanation:

<u />

<u>Equation 1:</u>

5 (x+8) +3

First, we can distribute the 5 to the (x+8) and get 5x + 40. Distributing is when we multiply the 5 by the first number (x) and then by the second number (8) Because they aren't like terms (don't both have x's) we cannot combine then and must keep them separated by a subtraction sign

Now we have: 5x + 40 + 3

Next, we can combine the like terms. This means that any that have the same variable can be combined. So, the 5x has no other x's so he has to stay how he is. The 40 and the 3, however, can be added together to get 43.

Our finished equation is: 5x + 43

<u />

<u>Equation 2:</u>

3.6x - 7 - 5.1x

First, we can combine like terms as we learned in the last problem. This would be our x's since we have multiple.

We can add 3.6x and -5.1x and get -1.5x

Now we have: -1.5x - 7

<u />

<u>Equation 3:</u>

4 + 8x + 2.2 - 10x

We can start with either the numbers with x's or without but I'll just do the x's. So we have 8x and -10x. Adding these together would get us -2x.

Next, we can combine 4 and 2.2 and get 6.2.

Now, putting these back into our equation would look like this:

6.2 - 2x

I'm not sure how much my explanations helped, but I hope you understand!!

8 0
3 years ago
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