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Effectus [21]
3 years ago
11

How is Solving for speed similar to solving for time? They both require that two numbers be added. They both require that two nu

mbers be subtracted. They both involve writing a rate OThey both Use the same units of measure
PLEASE HELP ME!!!!!!​
Mathematics
2 answers:
sweet [91]3 years ago
7 0

Answer:

They both involve writing a rate.

Step-by-step explanation:

EDGENUITY ANSWER

Zepler [3.9K]3 years ago
3 0

Answer:

NO im not helping you.

its c

Step-by-step explanation:

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Which of the following could be the equation of the graph shown below? Check all that apply.
Mashutka [201]

Answer:

y = -2x + 5

Х-y= 9

2x + y = 4

y = 5

lmk if incorrect, please give brainliest

8 0
3 years ago
On a very cold morning, it was -8°F. As the day went on, the temperature rose 2° each hour. which equation shows the temperature
gladu [14]
-8 + 2x
hope that helps
7 0
3 years ago
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Change this Mixed number into a improper fractions: 3 and 6/8
WITCHER [35]

Answer:

30/8

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please I’ve attached the question can you help me
Andreyy89

Answer:

1. <em>n</em>[(A U B) - C] = {23, 24, 27, 29, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 61, 63}

2. <em>n</em>[(A - B) U C] = <em>n</em>[A U C] = {6, 10, 12, 15, 20, 23, 29, 30, 31, 37, 41, 43, 47, 53, 59, 60, 61}

3. D. I, II and III.

Step-by-step explanation:

U = {21, 22, 23, ..., 64}

A prime number is a number that can be divided only by 1 and itself.

A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

B = {24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63}

C = {6, 10, 12, 15, 20, 30, 60}

1. Find <em>n</em>[(A U B) - C]

<em>n</em>(A U B) = {23, 24, 27, 29, 30, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 60, 61, 63}

<em>n</em>[(A U B) - C] = {23, 24, 27, 29, 30, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 60, 61, 63} - {6, 10, 12, 15, 20, 30, 60}

Since only 30 and 60 are common to <em>n</em>(A U B) and C, we therefore remove them it and have:

<em>n</em>[(A U B) - C] = {23, 24, 27, 29, 33, 36, 37, 39, 41, 42, 43, 45, 47, 48, 51, 53, 54, 57, 59, 61, 63}

2. Find <em>n</em>[(A - B) U C]

To get <em>n</em>(A - B) we remove all the elements of B in A. Since there are no common elements between A and B, we therefore have:

A - B = A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

C = {6, 10, 12, 15, 20, 30, 60}

Therefore, we have:

<em>n</em>[(A - B) U C] = <em>n</em>[A U C] = {6, 10, 12, 15, 20, 23, 29, 30, 31, 37, 41, 43, 47, 53, 59, 60, 61}

3. Which of the following is/are true?

I. A ∩ B = A ∩ C

A ∩ B = ∅

A ∩ C = ∅

Therefore, A ∩ B = A ∩ C is true.

II. A - B = A - C

A - B = A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

A - C = A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

Therefore, A - B = A - C is true.

III. A ∩ (B ∪ C) = ∅

A = {23, 29, 31, 37, 41, 43, 47, 53, 59, 61}

B U C = {6, 10, 12, 15, 20, 24, 27, 30, 33, 36, 39, 42, 45, 48, 51, 54, 57, 60, 63}

Therefore, A ∩ (B ∪ C) = ∅ is true.

Therefore, the correct option is D i.e. I, II and III are true.

4 0
3 years ago
Find the solution to the system of equations represented by this matrix equation using an inverse matrix.
8090 [49]

Answer:

  D) \left[\begin{array}{c}\frac{5}{4}\\-\frac{1}{2}\end{array}\right]

Step-by-step explanation:

For matrix \left[\begin{array}{cc}a&b\\c&d\end{array}\right]

the inverse matrix is the transpose of the cofactor matrix, divided by the determinant: \dfrac{1}{ad-bc}\left[\begin{array}{cc}d&-b\\-c&a\end{array}\right]

Your inverse matrix is: \dfrac{1}{2(-3)-(1)(2)}\left[\begin{array}{cc}-3&-1\\-2&2\end{array}\right]

so the solution is ...

\left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{cc}\frac{3}{8}&\frac{1}{8}\\\frac{1}{4}&-\frac{1}{4}\end{array}\right] \cdot\left[\begin{array}{c}2\\4\end{array}\right] =\left[\begin{array}{c}\frac{5}{4}\\-\frac{1}{2}\end{array}\right] \qquad\text{matches selection D}

4 0
3 years ago
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