(_/18+2_/3)^(2
=(3_/2^(2 + (2)(2_/3)(3_/2) + 2_/3^(2)
=18+ 12_/6 +12
=30+12_/6
hope this helps
=(3_/2^(2 + (2)(2_/3)(3_/2) + 2_/3^(2)
=18+ 12_/6 +12
=30+12_/6
hope this helps
Manuel se ha gastado 2/8 partes de la paga en ropa y 1/12 parte en dulces. ¿Qué fracción de la paga le queda?, ¿Si le dieron 45€
1 answer:
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Answer:
The probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95
Step-by-step explanation:
Number of red marbles = 12
Number of green marbles = 8
Total number of marbles = 12+8 = 20
Probability of selecting red marble =
Since it is the case of no replacement
Remaining marbles = 20-1 = 19
Number of red marbles = 12-1=11
Number of green marbles = 8
Probability of selecting green marble =
So, the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag =
Hence the probability of selecting a red marble, not replacing it, and then selecting a green marble from the bag is 24/95