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Kitty [74]
3 years ago
3

PLEASE HELP 100 points I’m on a time(there’s a picture) With respect to air safety, in which year between 1966 and 1976 did the

lowest number of air fatalities occur, and how
many passengers were killed in that year?
Year:1976,1974,1975
Passengers killed: 552,441,386

Mathematics
1 answer:
Degger [83]3 years ago
8 0

Looking at the column for number of passengers killed.

The lowest year was 1975 with 441 killed.

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Is (0.3) the solution to the equation y=x+3
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The ratio of boys to girls in history class is 4to5 how many girls are in class if there are 12 boys in the class
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What is 2 3/12 minus 1 8/12 equal to?​
ArbitrLikvidat [17]

Answer:

7/12

Step-by-step explanation:

3/12=1/4

2 1/4=9/4

8/12=2/3

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Andre45 [30]

Answer:

a_n=-3(3)^{n-1} ; {-3,-9, -27,- 81, -243, ...}

a_n=-3(-3)^{n-1} ; {-3, 9,-27, 81, -243, ...}

a_n=3(\frac{1}{2})^{n-1} ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

a_n=243(\frac{1}{3})^{n-1} ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

a_n=-3(3)^{n-1}

At n=1,

a_1=-3(3)^{1-1}=-3

At n=2,

a_2=-3(3)^{2-1}=-9

At n=3,

a_3=-3(3)^{3-1}=-27

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

a_n=-3(-3)^{n-1}

At n=1,

a_1=-3(-3)^{1-1}=-3

At n=2,

a_2=-3(-3)^{2-1}=9

At n=3,

a_3=-3(-3)^{3-1}=-27

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

a_n=3(\frac{1}{2})^{n-1}

At n=1,

a_1=3(\frac{1}{2})^{1-1}=3

At n=2,

a_2=3(\frac{1}{2})^{2-1}=1.5

At n=3,

a_3=3(\frac{1}{2})^{3-1}=0.75

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

a_n=243(\frac{1}{3})^{n-1}

At n=1,

a_1=243(\frac{1}{3})^{1-1}=243

At n=2,

a_2=243(\frac{1}{3})^{2-1}=81

At n=3,

a_3=243(\frac{1}{3})^{3-1}=27

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0
4 years ago
Prove the following using a direct proof:
hodyreva [135]

Answer:

Step-by-step explanation:

Prove: That the sum of the squares of 4 consecutive integers is an even integer.

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Selecting 4 consecutive positive integers: 5, 6, 7, 8. Then;

5^{2} = 25

6^{2} = 36

7^{2} = 49

8^{2} = 64

The sum of the squares = 25 + 36 + 49 + 64

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Also,

Selecting 4 consecutive negative integers: -10, -11, -12, -13. Then;

-10^{2} = 100

-11^{2} = 121

-12^{2} = 144

-13^{2} = 169

The sum of the squares = 100 + 121 + 144 + 169

                                     = 534

Therefore, the sum of the squares of 4 consecutive integers is an even integer.

8 0
3 years ago
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