Answer:
first one : x=−2y−5z−17
2nd one: x=
3
/2
y−z−8
3rd one: x=
−1
/3
y+
1
/3
z+1
Step-by-step explanation:
If X is increased by 7 to make 21
X + 7 = 21
then rearrange the equation to get X
X = 21-7
X = 14(b)
Answer:
Hence after 3.98 sec i.e 4 sec Object will hit the ground .
Step-by-step explanation:
Given:
Height= 6 feet
Angle =28 degrees.
V=133 ft/sec
To Find:
Time in seconds after which it will hit the ground?
Solution:
<em>This problem is related to projectile motion for objec</em>t
First calculate the Range for object and it is given by ,
(2Ф)/
Here R= range g= acceleration due to gravity =9.8 m/sec^2
1m =3.2 feet
So 9.8 m, equals to 9.8 *3.2=31.36 ft
So g=31.36 ft/sec^2. and 2Ф=2(28)=56


fts
Now using Formula for time and range as

Vx is horizontal velocity
Ф
(28)
ft/sec
So above equation becomes as ,


T is approximately equals to 4 sec.
The graph of the linear equation can be seen in the image below.
<h3 /><h3>How to graph the linear equation?</h3>
Here we have the linear equation:
y = (2/5)*x - 6
To graph it, we just need to find two points on the line, and then connect them with a line.
To find the points we just evaluate in two values of x.
if x = 0.
y = (2/5)*0 - 6 = -6
Then we have the point (0, -6)
If x = 5.
y = (2/5)*5 - 6 = 2 - 6 = -4
Then we have the point (5, - 4)
Now we can graph these two points and connect them with a line. The graph of the line can be seen below.
If you want to learn more about linear equations:
brainly.com/question/1884491
#SPJ1
Answer:
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