<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
60 out of 100 scores are passing scores, hence 
95% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).
- The lower limit is 0.5.
- The upper limit is 0.7.
A similar problem is given at brainly.com/question/16807970
Answer:
the answer is 2
Step-by-step explanation:
Used graph
232y-intercept: (0,3)(0,3)xy0326
Multiply 80 the way you would 100 to get the answer. 100 times .032 equals 3.2, therefore 80 times .032 equals the answer. (2.56)
Answer:
Step-by-step explanation:
Please present these numbers as a list: 7, -21, 63, -189, ....
Otherwise it appears that you are adding them up, which is not the case.
We can tell that this is a geometric series because each new number is -3 times the previous number: -3(7) = -21, -3(-21) = 63, and so on. Let r = -3 and a = first number = 7.
a
The sum of an infinite geometric series exists if and only if |r} < 1. Here, |-3|, or 3, so in this case the sum of the series does not exist. That is, the series diverges.
