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Sloan [31]
3 years ago
13

How do the lengths of the two vectors compare?

Geography
2 answers:
yarga [219]3 years ago
7 0

Answer: If contents of vectors are equal than it will return true else false. It will compare all the elements in vector, we can not compare the sub sections of vectors using it. It will compare all the elements in vector, by calling operator on each element. Hopefully i helped

Explanation:

elena-s [515]3 years ago
4 0
A vector quantity has two characteristics, a magnitude and a direction. When comparing two vector quantities of the same type, you have to compare both the magnitude and the direction. ... The length of the arrow indicates the magnitude and the tip of the arrow indicates the direction.
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Find the consecutive integers so that 4 times the square of the third decreased by 3 times the square of the first is 41 more th
Eddi Din [679]
Remark
We have to assume that there are only 3 consecutive integers.

Givens
Let the smallest integer = x
Let the middle integer = x + 1
Let the largest integer = x + 2

Formulas
4(x + 2)^2 - 3x^2 = 41+ 2*(x + 1)^2 Expand the brackets.

Solution
4(x^2 + 4x + 4) - 3x^2 = 41 + 2(x^2 + 2x + 1)  Remove the brackets.
4x^2 + 16x + 16 - 3x^2 = 41 + 2x^2 + 4x + 2   Collect like terms on both sides
x^2 + 16x + 16 =2x^2 + 4x + 43                       Subtract the left side from the right

0 = 2x^2 - x^2 - 16x + 4x - 16 + 43                  Collect like terms.
0 = x^2 - 12x + 27                                            This factors
(x - 3) * (x - 9)  = 0

x - 3 = 0
x = 3        or
x - 9 = 0
x = 9

Therefore numbers can be 3,4,5 or 9,10,11

We need to check both.
First group check.
Group One
4*5^2 - 3*3^2 = 41 + 2*4^2
4*25 - 3*9 = 41 + 2*16
100 - 27 = 41 + 32
73 = 73
Group one is correct.

Group Two
4*11^2 - 3*9^2 = 41 + 2*10^2
484 - 243 = 41 + 200
241 = 241 and the second group checks as well. So thee are two sets of answers.

3,4,5 and 9,10,11 <<<<<< Answer.
Note: You should put this in math.

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