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densk [106]
2 years ago
6

Could you tell me the answer to this problem −54.9 − (−18.75)

Mathematics
1 answer:
trapecia [35]2 years ago
4 0
The answer is -36.15
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Answer:

5 x Square root:2

Step-by-step explanation:

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Matt and Cat win £120 on the lottery and decide to share the winning ratio 1:2
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The way to work out how much each person gets is to find out how much one part is worth.

We can do this by adding the ratio (1:2) which gives us 3.

Divide £120 by 3 parts and you get £40 as one part. 

Because the ratio is one part : two parts, Matt gets £40 and Cat gets £80. 
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A rectangular picture 6cm by 8cm is enclosed by a frame 1/2cm wide . calculate the area of the frame.​
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Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5
Gennadij [26K]

Answer:

Points J and K could be located at:

J(2,2)

K(6,2)

Step-by-step explanation:

Consider the vertices have a x and y coordinate:

A: x coordinate=-7  y coordinate=-2

B: x coordinate=1  y coordinate=-2

C: x coordinate=1  y coordinate=-8

D: x coordinate=-7  y coordinate=-8

G: x coordinate=2  y coordinate=5

H: x coordinate=6  y coordinate=5

Then it is possible to calculate the distance between the x and y coordinates:

x coordinate of Vertices AB:

x coordinate of B- x coordinate of A=1-(-7)=8

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y coordinate of A- y coordinate of C=-2-(-8)=6

The distance between A and C is 6

Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.

Repeat the analysis  with Rectangle GHJK. In this case, is only possible to calculate the distance with x coordinate.

x coordinate of Vertices GH:

x coordinate of H- x coordinate of G=6-(2)=4

The distance between G and H is 4

We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that <em>the measure of ABCD is twice GHJK.</em>

Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in<em> y coordinate of Vertices GJ is 3.</em>

<em />

Points J and K could be located at:

J(2,2)

K(6,2)

3 0
3 years ago
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