Which code is an example of XHTML?

In some cases, certain Hyper-V guest operating system features do not function properly using the operating system's own device

klasskru [66]

Answer:

The correct answer to the following question will be "Guest Integration Service".

Explanation:

Integration resources are often a packaged package of applications that enhances connectivity between the hosting network as well as the virtual device when enabled throughout the VM.

This also seamlessly integrates time between both the visitors and server OS and could provide a pulse and folder compatibility.
It offers a Hyper-V network interface for unidirectional copying of data from and to another virtual machine.

This package of tools will help to fix compatibility problems. So, that is the right answer.

8 0

4 years ago

Leslie’s parents put a big dry-erase board on the refrigerator and let the kids write suggestions for how to organize and assign

blondinia [14]

Answer

determine possible solutions

Explanation:

im assuming

ty for the thanks

5 0

2 years ago

Draw a circuit with a 12-volt battery, a 100 ohms resistor in series, and two resistors (each of value 200 ohms) in parallel. Wh

amid [387]

Answer:

200 Ω

Explanation:

Hi there!

Please see below for the circuit diagram.

<u>1) Find the total resistance of the resistors in parallel</u>

Total resistance in parallel equation: $\frac{1}{R_T} = \frac{1}{R_1} +\frac{1}{R_2}$

Both the resistors measure 200 Ω. Plug these into the equation as R₁ and R₂:

$\frac{1}{R_T} = \frac{1}{200} +\frac{1}{200}\\\frac{1}{R_T} = \frac{1}{100}\\R_T=100$

Therefore, the total resistance of the resistors in parallel is 100 Ω.

<u>2) Find the total resistance of the circuit</u>

Now, to find the total resistance of the circuit, we must add the 100 Ω we just solved for and the 100 Ω for the other resistor placed in series:

100 Ω + 100 Ω = 200 Ω

Therefore, the total resistance of the circuit is 200 Ω.

I hope this helps!

7 0

3 years ago

How to engage more underrepresented and under resourced students in stem programs?

Nady [450]

Answer:

Through after school programs

Explanation:

Under represented and under resourced students can be better engaged in STEM programs through the establishment of after school state of the arts learning centres that can augment for the vacuum in the regular school system.

In such programs, the use of technological platforms with an integrated electronic learning system is necessary, because it avails the students the opportunity to brace up with the evolving impact of information technology to learning and personal developments.

Secondly, the use of immediate resources within the reach of these under privileged and under resourced students is a necessity. for example, a student in a rural community could start become more engage in engineering designs, building technology, instrumentation and architecture through the use of disposed cartons used to construct buildings, cars etc.

8 0

3 years ago

Write a C program to implement a command called displaycontent that takes a (text) file name as argument and display its conte

Zanzabum

Answer:

/*

Student: Hugo Meza

Date: February 15, 2019

Description: This program mimic the cat command from Linux. Checks whether the source file

has the right permissions, and then writes in the console its content.

*/

#include <stdio.h>

#include <fcntl.h>

#include <unistd.h>

#include <errno.h>

int hasPermission(char *filepath){

int returnval;

// Check file existence

returnval = access (filepath, F_OK);

if(errno == ENOENT){

printf ("%s does not exist\n", filepath);

return 0;

}

else if (errno == EACCES){

printf ("%s is not accessible\n", filepath);

return 0;

}

// Check read access

returnval = access (filepath, R_OK);

if(errno == ENOENT){

printf ("%s does not have read access\n", filepath);

return 0;

}

else if (errno == EACCES){

printf ("%s is not accessible\n",filepath);

return 0;

}

// Check write access

returnval = access (filepath, W_OK);

if(errno == ENOENT){

printf ("%s does not have read access\n", filepath);

return 0;

}

else if (errno == EACCES){

printf ("%s is not accessible\n",filepath);

return 0;

}

return 1;

}

int main(int argc, char* argv[]){

if(!argv[1]){

printf("Error. Specify file to open\n");

return 0;

}

int fd;

char *fp = argv[1], content[fd];

if(hasPermission(fp) == 0)

return 1;

fd = open(fp, O_RDONLY);

int bytes = read(fd,content,sizeof(content)-1);

write(1, content, bytes);

close(fd);

return 0;

}

Explanation:

7 0

3 years ago