1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mart [117]
2 years ago
7

At John Dean High School, 42

Mathematics
1 answer:
son4ous [18]2 years ago
5 0
C.48

110 students
- 42 photography
———
68

Now you must account for the fifteen who are in dual enrollment so 35-15=20

68
- 20
____
48
You might be interested in
Adam buys a box of stuff that weighed 6 3/8. if he buys box of fruit that weighed 7 2/5. what is the combined weight.
jolli1 [7]

Answer:

The combined weight is 13 31/40.

Step-by-step explanation:

Given:

Adam buys a box of stuff that weighed 6 3/8. if he buys box of fruit that weighed 7 2/5.

Now, to find the combined weight.

So, we change the mixed fraction to improper first:

Weight of box of stuff = 6\frac{3}{8}=\frac{51}{8}.

Weight of box of fruit  = 7\frac{2}{5}=\frac{37}{5}.

Then, by adding to get the combined weight:

\frac{51}{8}+\frac{37}{5}

=\frac{51\times 5+37\times 8}{40}

=\frac{255+296}{40}

=\frac{551}{40}

=13\frac{31}{40}

Therefore, the combined weight is 13 31/40.

4 0
3 years ago
Find the quadratic function that fits curve below. Select the correct answer.
raketka [301]
<h2>Hello!</h2>

The answer is:

The quadratic function that fits the given picture is:

y=-3x^{2}+13x-5

<h2>Why?</h2>

We can solve the problem and find the correct function that fits the curve below by finding which function intercepts the y-axis at -5 (we can see it from the picture), also, we need to look for a function that represents a parabola opening upwards. We need to remember that when a parabola is opening upwards, its quadratic term coefficient is negative.

So, we can see that from the given functions, the only function that represents a parabola opening upwards and its y-intercept is located at y equal to -5 is the second option:

y=-3x^{2}+13x-5

We have that :

a=-3(negative)\\b=13\\c=-5(y-intercept)

We can see that the quadratic term (a) is negative, and the quadratic function intercepts the y-axis at y equal to -5.

Hence, the answer is:

The quadratic function that fits the given picture is:

y=-3x^{2}+13x-5

Have a nice day!

Note: I have attached a picture for better understanding.

4 0
3 years ago
Hello I hope you have a wonderful day can you pls help me out it I will fail
ASHA 777 [7]
A. Independent goes on the x axis and dependent goes on the y axis
B. It shows his or hers miles per hour or mph or distance they run in a hour

Hope this helps have a great Monday ❤️
5 0
3 years ago
Which system of equations can you use to find the roots of the equation? x3 – 10x = x2 – 6 y = x3 – x2 + 10x + 6 y = 0 y = x3 –
Maslowich

Answer:

answer is:

y=x^{3}-10 x,y=x^{2}-6

Step-by-step explanation:

we are asked to find which system of equations can we use to find the roots of the equation:

x^{3}-10x=x^{2}-6

since the system of equation in last part is given as:

y=x^{3}-10 x,y=x^{2}-6

so, on equating both the equations i.e. on equating both the values of 'y' we get the desired equation as:

x^{3}-10x=x^{2}-6.


3 0
3 years ago
Read 2 more answers
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
Other questions:
  • Chloe notices that segment ST and segment VW are congruent in the image below.
    6·1 answer
  • 16x^2-1=0<br> help algebra 2
    10·1 answer
  • The seismic activity density of a region is the ratio of the number of earthquakes during a given time span to the land area aff
    8·2 answers
  • Subtract, 43 min 50 s - 4 min 8 s 43 min 49 s 39 min 35 s d. 39 min 42 s b. 51 min 42 s Please select the best answer from the c
    8·1 answer
  • Factor completely and then place the factors in the proper location on the grid. x 2 - 10x + 24
    9·1 answer
  • 200 students, which was 40% of the 7th graders said that the dress code was an important issue at school. How many students are
    10·1 answer
  • What will be the new position of the given point (–2, –3) after reflection across the x-axis?
    10·2 answers
  • #3 need help asap will give brainly
    5·1 answer
  • HELP ME PLS I REALLY NEEDD HELP!!!! MATH IS HORRIBLE
    12·1 answer
  • PLEASE HELP ME I DONT KNOW THE ANSWERR
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!