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2 years ago

Identify the linear inequality from the graph

Mathematics

1 answer:

Dovator [93]2 years ago

5 0

Answer:

B) y < 3/4x -2

Step-by-step explanation:

First, to eliminate 2 options let's see what sign we should use. The ≤ is a solid line where < is a dotted line. Next, you need to know which way to flip the sign. If it is under the line it is the < symbol.

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PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!

Llana [10]

Define your two QUESTIONS

Write your system of EQUATIONS

SOLVE the system of equations.

Find the SOLUTION to the question being asked.

6 0

2 years ago

Select the type of equations

olya-2409 [2.1K]

Two lines are "inconsistent" if they are parallel. They are "equivalent" if they are the same line. Otherwise, they are "consistent."

Your first 3 graphs show "consistent" equations.

The 4th graph shows "inconsistent" equations.

The solution shown on the 5th graph is where the lines intersect, near point
(5, 3)

4 0

3 years ago

Read 2 more answers

Suppose that a sample mean is .29 with a lower bound of a confidence interval of .24. What is the upper bound of the confidence

Ganezh [65]

Answer:

The upper bound of the confidence interval is 0.34

Step-by-step explanation:

Here in this question, we want to calculate the upper bound of the confidence interval.

We start by calculating the margin of error.

Mathematically, the margin of error = 0.29 -0.24 = 0.05

So to get the upper bound of the confidence interval, we simply add this margin of error to the mean

That would be 0.05 + 0.29 = 0.34

3 0

3 years ago

Which is more, 300 liters or 3 hectoliters?

BartSMP [9]

Answer: There equal

Step-by-step explanation:

multiply by 10

5 0

3 years ago

Read 2 more answers

Of the travelers arriving at a small airport, 60% fly on major airlines, 20% fly on privately owned planes, and the remainder fl

dmitriy555 [2]

Answer:

a) 0.55 = 55% probability that the person is traveling on business

b) 0.14 = 14% probability that the person is traveling for business on a privately owned plane.

c) 0.2545 = 25.45% probability that the person arrived on a privately owned plane, given that the person is traveling for business reasons.

d) 0.2 = 20% probability that the person is traveling on business, given that the person is flying on a commercially owned plane.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

Question a:

50% of 60%(major airlines)

70% of 20%(privately owned airplanes)

80% of 100 - (60+20) = 20%(comercially owned airplanes). So

$p = 0.5*0.5 + 0.7*0.2 + 0.8*0.2 = 0.55$

0.55 = 55% probability that the person is traveling on business.

Question b:

70% of 20%, so:

$p = 0.7*0.2 = 0.14$

0.14 = 14% probability that the person is traveling for business on a privately owned plane.

Question c:

Event A: Traveling for business reasons.

Event B: Privately owned plane.

0.55 = 55% probability that the person is traveling on business.

This means that $P(A) = 0.55$

0.14 = 14% probability that the person is traveling for business on a privately owned plane.

This means that $P(A \cap B) = 0.14$

Desired probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.14}{0.55} = 0.2545$

0.2545 = 25.45% probability that the person arrived on a privately owned plane, given that the person is traveling for business reasons.

Question d:

Event A: Commercially owned plane.

Event B: Business

80% of those arriving on other commercially owned planes are traveling for business reasons.

This means that:

$P(B|A) = 0.2$

0.2 = 20% probability that the person is traveling on business, given that the person is flying on a commercially owned plane.

5 0

3 years ago