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olchik [2.2K]
3 years ago
7

PLEASE HELP THIS QUESTION IS SO ANNOYING!!

Mathematics
2 answers:
shtirl [24]3 years ago
7 0
THE ANSWER IS 23,76 !!!
nikklg [1K]3 years ago
6 0
ANSWER- 23 , 76


Explanation- just did it :)
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Is -6 + -87 positive or negative?
drek231 [11]

Answer:

negative

Step-by-step explanation:

Brainliest me pls

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3 friendship 56 cards equally how many cards does each girl get how many cards are left over.
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how would you write " The sum of one-third of a number, one-half of a number,and twice the number is thirty-four" as an equation
Rudik [331]

Answer:  The required equation is \dfrac{1}{3}x+\dfrac{1}{2}x+2x=34.

Step-by-step explanation: We are given to write the following statement as an equation :

"The sum of one-third of a number, one-half of a number and twice the number is thirty-four".

Let the number be represented by x.

Then, one-third of the number is \dfrac{1}{3}x, one-half of the number is \dfrac{1}{2}x and twice the number is 2x.

Therefore, as an equation, the given statement is written as:

\dfrac{1}{3}x+\dfrac{1}{2}x+2x=34.

Thus, the required equation is \dfrac{1}{3}x+\dfrac{1}{2}x+2x=34.

4 0
3 years ago
A coupon offers a dollar off the 16 ounce size which size is the better buy
nevsk [136]
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3 years ago
The distance by rail from Leicester to Londonis 100 miles.
Zarrin [17]

The arrival time in london of a train that leaves Leicester to london at 11:50 A.M is 13:05 pm.

To calculate the arrival time in london of a train that leaves Leicester to london at 11:50 A.M, use use the formula below.

Formula:

  • Ta = [(d/s)+11:50]....... Equation 1

Where:

  • Ta = Arrival time
  • d = distance from Leicester to London
  • s = Speed

From the question,

Given:

  • d = 100 miles
  • s = 80 mph

Substitute these values into equation 1

  • Ta = [(100/80)+11:50]
  • Ta = 1.25h+11:50
  • Ta = 1 hours 15 minutes +11:50
  • Ta = 13:05 pm

Hence, the arrival time in london of a train that leaves Leicester to london at 11:50 A.M is 13:05 pm.

Learn more about time here: brainly.com/question/4931057

5 0
2 years ago
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