Y=3x-5
Y=5/4x+3/4
The solution to the equations is in the picture
The statement that correctly describes the product, 5.15 x 6√7, which is 81.7537155..., is <u>A. </u><u>irrational</u>.
<h3>What is an irrational product?</h3>
An irrational number is one that can be written as a decimal, but not as a fraction.
An irrational number has endless non-repeating digits to the right of the decimal point.
The rules for determining if a product is rational or irrational are as follows:
- The product of two rational numbers is rational.
- The product of a rational number and an irrational number is irrational.
- The product of two irrational numbers is irrational.
<h3>Data and Calculations:</h3>
5.15 x 6√7
= 5.15 x 6 x 2.64575...
= 81.7537155...
Thus, the product of 5.15 x 6√7 is irrational because √7 is irrational.
Learn more about rational and irrational numbers at brainly.com/question/20400557
#SPJ1
<h3>Complete Question with Answer Options:</h3>
Which of the following correctly describes the product below?
5.15 x 6√7
A. irrational
B. neither rational nor irrational
C. a combination of both rational and irrational
D. rational
Answer:
102 ≤ heart rate ≤ 183.6
Step-by-step explanation:
... lower limit ≤ heart rate ≤ upper limit
Put 16 where "a" is and do the arithmetic.
... lower limit = 0.5(220 -16) = 102
... upper limit = 0.9(220 -16) = 183.6
Then the inequality is ...
... 102 ≤ heart rate ≤ 183.6
_____
<em>Comment on the problem</em>
There is nothing to "solve" here. One only needs to evaluate the limits.
Yes, the set of vectors
V = {(x, y, z) : x - 2y + 3z = 0}
is indeed a vector space.
Let u = (x, y, z) and v = (r, s, t) be any two vectors in V. Then
x - 2y + 3z = 0
and
r - 2s + 3t = 0
Their vector sum is
u + v = (x + r, y + s, z + t)
We need to show that u + v also belongs to V - in other words, V is closed under summation. This is a matter of showing that the coordinates of u + v satisfy the condition on all vectors of V:
(x + r) - 2 (y + s) + 3 (s + t) = (x - 2y + 3z) + (r - 2s + 3t) = 0 + 0 = 0
Then V is indeed closed under summation.
Scaling any vector v by a constant c gives
cv = (cx, cy, cz)
We also need to show that cv belongs to V - that V is closed under scalar multiplication. We have
cx - 2cy + 3cz = c (x - 2y + 3z) = 0c = 0
so V is need closed under scalar multiplication.
Answer:
where are the options
Step-by-step explanation:
