The graph that has an axis of symmetry at x = 3 is f(x) = x2 – 6x – 1.
You can find the axis of symmetry by using the equation to find the x value of the vertex. The x value of the vertex is always the axis of symmetry in a quadratic graph. The equation is below.
x = -b/2a
In this equation, a is the coefficient of x^2 and b is the coefficient of x. If we use the numbers from the last equation in your list, a = 1, b = -6.
x = -b/2a
x = -(-6)/2(1)
x = 6/2
x = 3
y = x^2 - 3x - 4
Factored Form: y = (x - 4)(x + 1)
X-Intercepts: (4,0) and (-1,0)
Axis of Symmetry: x = 1.5
Vertex: (1.5, -6.25)
Domain: All real numbers
Range: y > -6.25
Hope this helps!
If I'm not wrong, then the answer will be:-
Given
• centers A, B, C
• three congruent sides
• have no common points
So, the result is:-
| PQ | + | RS | + | TU | = | QR | + | ST | + | UP |
<h3>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Proved </em></h3>
I hope this answer is correct and helps you.
✍️ <em>By </em><em>Benjemin</em> ☺️
42.
As
1 dozen is 12 eggs, 3 dozens of the eggs is 12×3=36.
half of a dozens is 6 so
36+6 =42
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