You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.
When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)
Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)
point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)
point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)
Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)
Hope this helps :)
Answer:
b. The slope is -10, and the y-intercept is 1.
Step-by-step explanation:
Y = slope(x) + y-intercept
<u>Answer</u>
748.23 in²
<u>Explanation</u>
Apothem a line from the centre of a regular polygon at right angles to any of its sides. This can be said to be the height of the triangle in a polygon.
The base of the hexagon = 101.8 ÷ 6
= 19.96666..
= 19.9667 inches
Area of the hexagon = 1/2 × height × base length × 6
= 1/2 × 14.7 × 19.9667 × 6
= 748.23 in²
