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3 years ago

What is the slope of the line represented by the equation f(t)=2t−6?

Mathematics

1 answer:

bagirrra123 [75]3 years ago

5 0

ANSWER: the answer is A

EXPLANATION: i know

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Find a point on the y-axis that is equidistant from the points (8, −8) and (1, 1).

artcher [175]

$\text{We know that any point on the y-axis is of the form (0, y),}\\
\text{because on y-axis we have x=0.}\\
\\
\text{So let (0, y) be the point on the y-axis that is equidistance from}\\
\text{the points }(8,-8) \text{ and }(1,1)\\
\\
\text{so using the distance formula, we have}\\
\\
\text{Distance between (0, y) and }(8,-8)=\text{Distance between (0,y) and }(1,1)\\
\\
\Rightarrow \sqrt{(0-8)^2+(y-(-8))^2}=\sqrt{(0-1)^2+(y-1)^2}$

$\Rightarrow \sqrt{64+(y+8)^2}=\sqrt{1+(y-1)^2}\\
\\
\text{Squaring both sides, we get}\\
\\
(\sqrt{64+(y+8)^2})^2=(\sqrt{1+(y-1)^2})^2\\
\\
\Rightarrow 64+(y+8)^2=1+(y-1)^2\\
\\
\Rightarrow 64+(y^2+16y+64)=1+(y^2-2y+1)\\
\\
\Rightarrow y^2+16y+128=y^2-2y+2\\
\\
\Rightarrow y^2+16y-y^2+2y=2-128\\
\\
\Rightarrow 18y=-126\\
\\
\Rightarrow y=\frac{-126}{18}\\
\\
\Rightarrow y=-7$

So the point on the y-axis that is equidistant from the points (8,-8) and (1,1) is: (0,-7)

3 0

4 years ago

Consider the line =−−8x6y1.

ICE Princess25 [194]

Answer:

Below

Step-by-step explanation:

Well I can't really see the equation but I can tell you how to do it.

Parallel slopes are the same slope as the equation.

For example, y = mx + b

The slope of a line parallel to it is m

Perpendicular slopes are the opposite reciprocal as the equation.

For example, y = mx + b

The slope of a line perpendicular to it is $-\frac{1}{m}$

6 0

3 years ago

Service Department Charges and Activity Bases

gladu [14]

The answers to the question are:

<h3>a. How to determine the service charge rate for the month of October</h3>

This is the number of calls for the help desk

160000/3200 = 50per call

network center

735000/9800

= 75 per device that was monitored

Electronic mail

100000/10000 =

10 for the mail account

For smart phone support

124600/8900

= 14 per phone extension

<h3>b. Charges to the COMM sector </h3>

for helpdesk

5200 * 0.25 * 0.96 *1.5 calls * $50

= 93600

For network center

(5200 * 0.25 * 0.96) + 600] x 75

= 138600

For Electronic mail

5200 * 0.25 * 0.96 * 10 per email account

= 12480

Smart support charge

5200 * 0.25 * 14 = 18200