Ask question

Ask question

All categories

3 years ago

11

You earn $9.20 per hour at your summer job. Identify an inequality that represents the number p of hours you need to work in ord

er to buy a smart phone that costs $299.

1 answer:

Korvikt [17]3 years ago

7 0

Answer:

$32.5

Step-by-step explanation:

I hope this helps.

You might be interested in

At the local nursery, 1/4 of the plants for sale are flowers and another 3/5 of them are bushes. What fraction of the plants for

Hitman42 [59]

Answer:

17/20

Step-by-step explanation:

1/4 +3/5 simplify into:

5/20 + 12/20= 17/20

5 0

2 years ago

Find the rule. Solve for n. Х 12 15 20 Y 7 10 15 17 n Rule:

Novosadov [1.4K]

Answer:

n =22

Step-by-step explanation:

12-5=7

15-5=10

20-5=15

n-5=17

collect like terms

n=17+5

n=22

4 0

2 years ago

Consider the function represented by the equation y-6x-9=0. Which answer shows the equation written in function notation with x

Marta_Voda [28]

Answer:

A. f(x) = 6x + 9

Step-by-step explanation:

The given equation is:

y - 6x - 9 = 0

We have to write this equation in function notation with x as the independent variable. This means that y will be replaced by f(x) and all other terms will be carried to the other side of the equation to get the desired function notation.

y - 6x - 9 = 0

y = 6x + 9

f(x) = 6x + 9

Therefore, option A gives the correct answer.

5 0

3 years ago

Read 2 more answers

Evaluate 12÷3·(-3) + |-8|<br><br> -20<br> -4<br> 20/3

olasank [31]

Answer:

-4

Step-by-step explanation:

6 0

3 years ago

Element X decays radioactively with a half life of 12 minutes. If there are 200 grams of Element X, how long, to the nearest ten

Semenov [28]

Answer:

It would take 24 minutes for the element to decay to 50 grams

Step-by-step explanation:

The equation for the amount of the element present, after t minutes, is:

$Q(t) = Q(0)e^{-rt}$

In which Q(X) decays radioactively with a half life of 12 minutes.(0) is the initial amount and r is the rate it decreases.

Half life of 12 minutes

This means that $Q(12) = 0.5Q(0)$

So

$Q(t) = Q(0)e^{-rt}$

$0.5Q(0) = Q(0)e^{-12r}$

$e^{-12r} = 0.5$

$\ln{e^{-12r}} = \ln{0.5}$

$-12r = \ln{0.5}$

$12r = -\ln{0.5}$

$r = -\frac{\ln{0.5}}{12}$

$r = 0.05776$

If there are 200 grams of Element X, how long, to the nearest tenth of a minute, would it take the element to decay to 50 grams?

This is t when Q(t) = 50. Q(0) = 200.

$Q(t) = Q(0)e^{-rt}$

$50 = 200e^{-0.05776t}$

$e^{-0.05776t} = 0.25$

$\ln{e^{-0.05776t}} = \ln{0.25}$

$-0.05776t = \ln{0.25}$

$0.05776t = -\ln{0.25}$

$t = -\frac{\ln{0.25}}{0.05776}$

$t = 24$

It would take 24 minutes for the element to decay to 50 grams

6 0

3 years ago