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vampirchik [111]
2 years ago
6

Need help question #2. Show steps please

Mathematics
1 answer:
RSB [31]2 years ago
3 0

Answer:

C

Step-by-step explanation:

We want to evaluate the definite integral:

\displaystyle \int_0^1 (x+2)(3x^2+12x+1)^{1/2}\, dx

Again, notice that the radicand is quite similar to the outside factor. So, we can use u-substitution again. We will let:

\displaystyle u=3x^2+12x+1

Then:

\displaystyle \frac{du}{dx}=6x+12

Hence:

\displaystyle du=6x+12 \, dx

And we can divide both sides by 6:

\displaystyle \frac{1}{6}\, du=x+2\, dx

Note that the limits of integration of our original integral (from x = 0 to x = 1) is in the domain of x. Since we changed variables, we should also change the limits of integration to u. So:

u(0)=3(0)^2+12(0)+1=1

And:

u(1)=3(1)^2+12(1)+1=16

Hence, our new limits of integration is from u = 1 to u = 16.

Perform the substitution:

\displaystyle =\int_{1}^{16} u^{1/2}\Big(\frac{1}{6}\, du\Big)

Simplify:

\displaystyle =\frac{1}{6}\int_1^{16}u^{1/2}\, du

Integrate:

\displaystyle =\frac{1}{6}\Big(\frac{2}{3}u^{3/2}\Big)\Big|_{1}^{16}

Simplify:

=\displaystyle \frac{1}{9}\Big(u^{3/2}\Big|_1^{16}\Big)

Evaluate:

\displaystyle =\frac{1}{9}\Big(16^{3/2}-1^{3/2}\Big)=\frac{1}{9}(64-1)=7

The answer is C.

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