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2 years ago

Find 165.1% of 333.Round to the nearest hundredth.

Mathematics

1 answer:

inysia [295]2 years ago

6 0

Answer:

We get that the 165.1% of 333 is 333 • 1.651 = 549.78

Step-by-step explanation:

1. They are asking for the 165.41%

2. So, we need to multiply 333 by the representation of 165.1% in decimal by doing the multiplication using a calculator

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I need help with this????

Mars2501 [29]

Answer:

Step-by-step explanation:

X is either larger than -1 or smaller than 3 which is demonstrated in the equation in option A

3 0

2 years ago

In a chess tournament, each player plays every other player exactly once. If it is known that 105 games were played, how many pl

diamong [38]

Answer:

15 players played in the chess tournament.

Step-by-step explanation:

When there are 15 players, the first player plays 14 games and step aside.

remaining 14 player

next player plays 13 games. steps aside

remaining 13 players

next player plays 12 games. steps aside

remaining 12 players

next player plays 11 games. steps aside

remaining 11 players

Last player plays 1 game and steps aside

remaining 1 player who will not play against himself.

∴ Sum of all games played

= 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 105 games played

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3 years ago

In Exercise 4, find the surface area of the solid<br> formed by the net.

Fittoniya [83]

Answer:

3. 150.72 in²

4. 535.2cm²

Step-by-step Explanation:

3. The solid formed by the net given in problem 3 is the net of a cylinder.

The cylinder bases are the 2 circles, while the curved surface of the cylinder is the rectangle.

The surface area = Area of the 2 circles + area of the rectangle

Take π as 3.14

radius of circle = ½ of 4 = 2 in

Area of the 2 circles = 2(πr²) = 2*3.14*2²

Area of the 2 circles = 25.12 in²

Area of the rectangle = L*W

width is given as 10 in.

Length (L) = the circumference or perimeter of the circle = πd = 3.14*4 = 12.56 in

Area of rectangle = L*W = 12.56*10 = 125.6 in²

Surface area of net = Area of the 2 circles + area of the rectangle

= 25.12 + 125.6 = 150.72 in²

4. Surface area of the net (S.A) = 2(area of triangle) + 3(area of rectangle)

= $2(0.5*b*h) + 3(l*w)$

Where,

b = 8 cm

h = $\sqrt{8^2 - 4^2} = \sqrt{48} = 6.9 cm} (Pythagorean theorem)w = 8 cm[tex]S.A = 2(0.5*8*6.9) + 3(20*8)$

$S.A = 2(27.6) + 3(160)$

$S.A = 55.2 + 480$

$S.A = 535.2 cm^2$

6 0

3 years ago

Answer the circle question please.

makkiz [27]

$\frac{11}{-6}$

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2 years ago

Dividir entre la raíz más cercana

inna [77]

Where is the question ?

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1 year ago