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Vera_Pavlovna [14]
3 years ago
12

Which data set represents the histogram?

Mathematics
1 answer:
9966 [12]3 years ago
3 0
Hey! In order for me to answer your question , I need more information thank you!









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Plz help me with this
9966 [12]

Answer:  c) y = ln(5x) - 2

<u>Step-by-step explanation:</u>

y=\dfrac{1}{5}e^{x+2}\\\\\text{Swap the x's and y's.  Then solve for y:}\\\\x=\dfrac{1}{5}e^{y+2}\\\\\\\text{Multiply both sides by 5:}\\5x=e^{y+2}\\\\\\\text{Apply ln to both sides:}\\ln(5x)=ln\ e^{y+2}\\\\\text{Simplify:}\\ln(5x)=y+2\\\\\\\text{Subtract 2 from both sides:}\\ln(5x)-2=y

8 0
3 years ago
The following function describes the number of employees working at a company, in thousands, where t represents the number of ye
Alex787 [66]

Answer:

The answer is (B)

Step-by-step explanation:

Try out each of the situations. It can't be A, since the 0.9 is less than 1, so it has to be decreasing. This leaves only B and C. Since decreasing by 90 percent is the same as multiplying by 10 percent, the only possible answer left is B.

Hope this helps!

8 0
3 years ago
Read 2 more answers
Help pleaseeeeee lol
andriy [413]

Answer:

7)m=-4

8)p=1

9)v=-12

10)n=-7

11)-13=x

12)b=-4

13)-108=b

14)n=4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The weights of cockroaches living in a typical college dormitory are approximately distributed with a mean of 80 grams and a sta
Romashka [77]

Answer:

The percentage of cockroaches weighing between 77 grams and 83 grams is about 55%.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 80, \sigma = 4

The percentage of cockroaches weighing between 77 grams and 83 grams

This is the pvalue of Z when X = 83 subtracted by the pvalue of Z when X = 83. So

X = 83

Z = \frac{X - \mu}{\sigma}

Z = \frac{83 - 80}{4}

Z = 0.75

Z = 0.75 has a pvalue of 0.7734

X = 77

Z = \frac{X - \mu}{\sigma}

Z = \frac{77 - 80}{4}

Z = -0.75

Z = -0.75 has a pvalue of 0.2266

0.7734 - 0.2266 = 0.5468

Rounded to the nearest whole number, 55%

The percentage of cockroaches weighing between 77 grams and 83 grams is about 55%.

7 0
4 years ago
Lowest common multiple between 10 and 19
lianna [129]

LCM between 10 and 19 is 190.

First we can find the prime factorization of 10:

2 * 5.

Prime factorization of 19:

19.

2 * 5 * 19 = 190

3 0
3 years ago
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