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grigory [225]
2 years ago
10

There are 32 marbles in a jar: 14 blue, 10 red, 5 green, and 3 yellow. Sally pulls one marble, randomly, from the jar. Without r

eplacing the marble, she pulls another marble. What is the probability that both marbles will be red?
Mathematics
2 answers:
Oduvanchick [21]2 years ago
6 0
What’s the answer or is a write ur self answer so I can help !
irakobra [83]2 years ago
3 0

Answer:45/496

Step-by-step explanation:

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Three fourths of a page are read in 2 minutes how many are read in one minute?
Dmitrij [34]

Answer:

3/8 of a page

Step-by-step explanation:

3/4=2 minutes

3/8 pages in a minute

You take 3/4 and divide by 2 to get 3/8

7 0
3 years ago
Solve the equation 0.4+0.5=-4.7-0.6z
Charra [1.4K]
0.9 = -4.7 - 0.6z
0.9 + 4.7 = -0.6z
5.6 = -0.6z
z = 5.6 ÷ -0.6
z = -9.33
7 0
3 years ago
A food bank is collecting cans to help people this Thanksgiving. The food bank started off with 40 cans of green beans and they
seropon [69]
75%  30/40= .75
Hope this helps 
7 0
3 years ago
Evaluate the expression 81÷ (14 − 5) × 2
Naddik [55]

Answer:

See below.

Step-by-step explanation:

81/(14-5)*2

81/9*2

9*2

18

-hope it helps

4 0
2 years ago
Read 2 more answers
(1) Let {v1,v2,v3} be a set of vectors in Rn . If u is Span {v1,v2,v3}, show that 3u is in Span {v1,v2,v3}.
Evgesh-ka [11]

Answer:

(1)

Multiplying by 3 both sides of the equality you get that

3u = 3c_1v_1+3c_2v_2+3c_3v_3

3u  is in the Span of the vectors \{v_1,v_2,v_3\}.

(2)

That's not true, consider the following counter example.

v_1 = (0,0,0,1)\\v_2 = (0,0,1,0)\\v_3 = (0,1,0,0)\\v_4 = (1,0,0,0)\\u = (0,1,1,1)

u is a linear combination of v_1,v_2,v_3 but is NOT a linear combination of v_1,v_2,v_3,v_4.

Step-by-step explanation:

(1)

As the hint indicates, you know that

u = c_1 v_1 + c_2v_2+c_3v_3

Then, if you multiply both sides of the equality by 3, you get that

3u = 3c_1v_1+3c_2v_2+3c_3v_3

And that's it. 3u  is in the Span of the vectors \{v_1,v_2,v_3\}

(2)

That's not true, consider the following counter example.

v_1 = (0,0,0,1)\\v_2 = (0,0,1,0)\\v_3 = (0,1,0,0)\\v_4 = (1,0,0,0)\\u = (0,1,1,1)

u is a linear combination of v_1,v_2,v_3 but is NOT a linear combination of v_1,v_2,v_3,v_4.

4 0
3 years ago
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