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anastassius [24]
2 years ago
9

Joel is buying packs of baseball cards to add to his collection. He wants to

Mathematics
1 answer:
antoniya [11.8K]2 years ago
5 0
Uh i’m not sure bud. bug
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Plz help me step by step explanation would help for work plzzzz And Thank you PLEASE​
AnnyKZ [126]

Answer:

i hope this helps

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
There are 50 pages in a chapter. Claire read 17 pages of the chapter on Sunday.
nexus9112 [7]

Answer:

She read 34% of the chapter

Step-by-step explanation:

You divide 17 by 50 and that gives you your answer

17/50=.34

move the decimal point 2 places to the right and the gives you your precent

.34=34%

5 0
3 years ago
Use synthetic division to determine whether the number k is an upper or lower bound (as specified for the real zeros of the func
mote1985 [20]

Solution:

The given Polynomial is :

f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5})

By Rational Root theorem the  of Zeroes of the Polynopmial are:

\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4

But , f(\pm\frac{1}{5},\pm\frac{2}{5},\pm\frac{4}{5},\pm1,\pm2,\pm4)\neq 0

So, no root of this polynomial is real.

Therefore, All the four roots of Polynomial are imaginary.

So, we can't say whether the number k=2, is an upper or lower bound of the polynomial f(x) = 5x^4 + 4x^3 - 2x^2 + 2x + 4=5( x^4 + \frac{4}{5}x^3 - \frac{2}{5}x^2 + \frac{2}{5}x + \frac{4}{5}).

8 0
3 years ago
Read 2 more answers
The following data points represent the number of attendees at each of the dance events hosted by Cloy
Viktor [21]
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 2: Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 3: Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).
Step 4: Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7),  9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.
Step 5: Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.

5 0
3 years ago
Use the identity a^3+b^3=(a+b)^3−3ab(a+b) to determine the sum of the cubes of two numbers if the sum of the two numbers is 4 an
olga55 [171]

Your identity says ...

... sum of cubes = (sum)³ -3(product)(sum)

... = 4³ -3·1·4

... = 64 -12 = 52

_____

The two numbers are 2±√3, and the sum of their cubes is indeed 52.

3 0
3 years ago
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