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Umnica [9.8K]
3 years ago
12

8) BRAINLIEST AND 15 POINTS! PLS HELP ASAP

Mathematics
1 answer:
algol133 years ago
4 0

Answer:

a.) Between 0.5 and 3 seconds.

Step-by-step explanation:

So I just went ahead and graphed this quadratic on Desmos so you could have an idea of what this looks like. A negative quadratic, and we're trying to find when the graph's y-values are greater than 26.

If you look at the graph, you can easily see that the quadratic crosses y = 26 at x-values 0.5 and 3. And, you can see that the quadratic's graph is actually above y = 26 between these two values, 0.5 and 3.

Because we know that the quadratic's graph models the projectile's motion, we can conclude that the projectile will also be above 26 feet between 0.5 and 3 seconds.

So, the answer is a.) between 0.5 and 3 seconds.

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The notation per capita simply means that the number is divided by the total population. Therefore the number of McDonald’s per capita in Canada 2013 is:

McDonald’s per capita = 1427 / 35,160,000

<span>McDonald’s per capita = 4.06 x 10^-5</span>

6 0
4 years ago
(a) <br> 127.5<br> is what percent of <br> 51<br> ?
ExtremeBDS [4]
To solve this, you need to divide 127.5 by 51:
127.5/51 = 2.5
To find the percent, multiply 2.5 by 100:
2.5 x 100% = 250%
So 127.5 is 250% of 51
8 0
3 years ago
In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home. Give the value of th
astra-53 [7]

Answer:

The value of the standard error for the point estimate is of 0.0392.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In a randomly selected sample of 100 students at a University, 81 of them had access to a computer at home.

This means that n = 100, p = \frac{81}{100} = 0.81

Give the value of the standard error for the point estimate.

This is s. So

s = \sqrt{\frac{0.81*0.19}{100}} = 0.0392

The value of the standard error for the point estimate is of 0.0392.

7 0
3 years ago
I posted one question at parts pls help me answer it!!!!!
Fantom [35]

Answer:

i'll try my best to help !!

5 0
3 years ago
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Sam opened a money account that pays 3 % simple interest. He started the account with 7000$ and made no further deposits. When h
Novosadov [1.4K]
He kept his account open for 3 years
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3 years ago
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