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Alborosie
3 years ago
8

Which equation is equivalent to

Mathematics
1 answer:
STALIN [3.7K]3 years ago
8 0

Answer:

C

Step-by-step explanation:

y + 2x + 10 = 4x + 5

y = 4x - 2x + 5 - 10

y = 2x - 5

Answer- C

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Find all points on the curve x=4cos(t),y=4sin(t) that have the slope of 12.
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Answer:

\left (-\dfrac{4}{\sqrt{5}},\dfrac{8}{\sqrt{5}}\right )\text{ and }\left (\dfrac{4}{\sqrt{5}},-\dfrac{8}{\sqrt{5}}\right ).

Step-by-step explanation:

We need to find all the points on the curve x=4cos(t),y=4sin(t) that have the slope of 1/2.

x=4cos (t)

\dfrac{dx}{dt}=-4sin (t)

y=4sin (t)

\dfrac{dy}{dt}=4cos (t)

Now,

\dfrac{dy}{dx}=\dfrac{dy}{dt}\times \dfrac{dt}{dx}

\dfrac{dy}{dx}=4cos (t)\times \dfrac{1}{-4sin (t)}

\dfrac{dy}{dx}=-\cot t

So, slope of the curve is -\cot t.

-\cot t=\dfrac{1}{2}

-\tan t=2

\tan t=-2            ...(1)

Using \sec^2t=1+\tan^2t, we get

\sec^2t=1+(-2)^2

\sec^2t=1+4

\sec t=\pm \sqrt{5}

\cos t=\pm \dfrac{1}{\sqrt{5}}

Now,

\sin^2t=1-cos^2t

\sin t=\pm \sqrt{1-\dfrac{1}{5}}

\sin t=\pm \sqrt{\dfrac{4}{5}}

\sin t=\pm \dfrac{2}{\sqrt{5}}

It equation (1), tan(t) is negative. So, sin and cos have different signs.

If \sin t= \dfrac{2}{\sqrt{5}}, then \cos t=- \dfrac{1}{\sqrt{5}}.

x=4cos (t)=-\dfrac{4}{\sqrt{5}}

y=4sin (t)=\dfrac{8}{\sqrt{5}}

If \sin t=- \dfrac{2}{\sqrt{5}}, then \cos t= \dfrac{1}{\sqrt{5}}.

x=4cos (t)=\dfrac{4}{\sqrt{5}}

y=4sin (t)=-\dfrac{8}{\sqrt{5}}

Therefore, the two points are \left (-\dfrac{4}{\sqrt{5}},\dfrac{8}{\sqrt{5}}\right )\text{ and }\left (\dfrac{4}{\sqrt{5}},-\dfrac{8}{\sqrt{5}}\right ).

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3 years ago
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Answer:

t < 0 and t > 140

Step-by-step explanation:

It is given in the question that fluid is not a liquid if its temperature is above 140°C or below 0°C.

So, the inequality that satisfies the temperature at which the fluid is liquid will be given by 140 ≥ t ≥ 0.

Now, the compound inequality for the temperature t when the fluid is not liquid is t < 0 and t > 140. (Answer)

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what’s transformation is the result of reflect in the original figure across the Y-axis and then across the X-axis
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Answer:

D

Step-by-step explanation:

When reflected across the Y it becomes B, but then across the X, it fits into D.

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