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Alenkinab [10]
3 years ago
5

Help who ever. actually helps me gets brainliest.​

Mathematics
1 answer:
Llana [10]3 years ago
3 0

Answer:

A, C

Step-by-step explanation:

6 boxes in 1/2 hour means 12 boxes in 1 hour (there are 2 half-hours in 1 hour) so multiply 6 by 2

dividing 6 by 1/2 is the same as multiplying 6 by 2

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What is the equation of the line containing the points (4, 2) and (−1, 5)? Write your
Minchanka [31]

Answer:

y=-3/5x+4 2/5

Step-by-step explanation:

6 0
3 years ago
Which of the descriptions is true for the graph
Flura [38]

Let's check every choices until one choices satisfy the graph :

Choice A is just a translation of -5 units or 5 units to the left

If we look at the graph between A"B"C" and A'B'C'

A"B"C" is 5 units to the left of A'B'C'

Therefore Choice A is True!

The correct answer is A.

No need to check for the other choices since you got a true statement at the first Choice.

IF in case that A is False, then you need to check the other choices.

5 0
2 years ago
In trapezoid ABCD with bases AB and DC , diagonals intersect at point O. Find the length of diagonal BD , if BO=6 cm and: AO/OC
aalyn [17]

Answer:

8 cm

Step-by-step explanation:

... BO/OD = AO/OC = 3/1

Written another way, this is ...

... OD : BO = 1 : 3

Now, BD = OD + BO, so we have

... BD : BO = (OD +BO) : BO = (1 +3) : 3 = 4 : 3

That is, BD = 4/3 × BO

... BD = 4/3 × 6 cm = 8 cm

6 0
3 years ago
Determime the intercepts of the line that passes through the following points. (-6,5);(-3,3);(0,1)
butalik [34]

well for a line, to get its slope all we need is two points, so let's use (-6, 5) and (0, 1), and get the equation of it.


\bf (\stackrel{x_1}{-6}~,~\stackrel{y_1}{5})\qquad
(\stackrel{x_2}{0}~,~\stackrel{y_2}{1})
\\\\\\
slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{1-5}{0-(-6)}\implies \cfrac{1-5}{0+6}\implies -\cfrac{5}{6}


\bf \begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-5=-\cfrac{5}{6}[x-(-6)]\implies y-5=-\cfrac{5}{6}(x+6)
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\textit{to get the x-intercept, we set y = 0, solve for \underline{x}}
\\\\\\
0-5=-\cfrac{5}{6}(x+6)\implies -30=5x+30\implies -60=5x
\\\\\\
\cfrac{-60}{5}=x\implies -12=x~\hfill \boxed{\stackrel{x-intercept}{(-12,0)}}


now, where's the y-intercept of that line?  well, to get the y-intercept, we set x = 0 and solve for "y"....hmmmm wait a second, notice (0, 1), x = 0, y = 1, that's the y-intercept already.

7 0
4 years ago
How high is a tree that cast a 26ft shadow at the same time a6ft post casts a shadow which is 11ft long
Norma-Jean [14]

Set up a ratio:

6/11 = x/26

Cross multiply:

11x = 156

Divide both sides by 11:

X = 14.18 feet ( round answer as needed.)

3 0
3 years ago
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