Please I need this question ASAP

Mathematics

1 answer:

makkiz [27]3 years ago

7 0

In order to find all of these, you first must convert the percentage to a decimal. This would be 13% to 0.13.

Now, multiply 0.13 by all of these into a calculator.

1800 • 0.13 = 234
950 • 0.13 = 123.50
2200 • 0.13 = 286
3000 • 0.13 = 390
2600 • 0.13 = 338

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What is the common difference of 80,60,45,33.75

GenaCL600 [577]

Answer:

The common difference (or common ratio) = 0.75

Step-by-step explanation:

i) let the first term be $a_{1}$ = 80

ii) let the second term be $a_{2}$ = $a_{1}$ . r = 80 × r = 60 ∴ r = $\frac{60}{80}$ = 0.75

iii) let the third term be $a_{3}$ = $a_{2}$ . r = 60 × r = 45 ∴ r = $\frac{45}{60}$ = 0.75

iv) let the fourth term be $a_{4}$ = $a_{3}$ . r = 45 × r = 33.75 ∴ r = $\frac{33.75}{45}$ = 0.75

Therefore we can see that the series of numbers are part of a geometric progression and the first term is 80 and the common ratio = 0.75.

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3 years ago

(1 point) Find y as a function of x if

Alenkasestr [34]

Y’’(x)= 6x + 1
y’(x)= 3x^2 + x + 2
y(x)= x^3 + 1/2x^2 + 2x + 5

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1 year ago

Please calculate this limit please help me

Tasya [4]

Answer:

We want to find:

$\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}$

Here we can use Stirling's approximation, which says that for large values of n, we get:

$n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n$

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

$\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} = \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}$