Answer:
y - 5 = 6(x + 2)
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
Here m = 6 and (a, b) = (- 2, 5) , then
y - 5 = 6(x - (- 2)) , that is
y - 5 = 6(x + 2)
The answer would be D 95.8.
You have to use the Pythagorean theorem to find the missing side length
So it would be 10 squared plus 12 squared equals 15.62
Then you double it because of the two top side lengths
Then you use the Pythagorean theorem for the bottom
12 squared plus 30 squared which equals 32.31
And you double that as well
31.24 plus 64.62 equals 95.86 and you just round to 95.8
True, y=7 means its just a horizontal line running straight through the 7 on the vertical/y-axis.
The true statement about the graph of the function f(x) = x3 - 2x2 + 4x – 8 is (B) The function has 1 real zero that occurs 1 time.
<h3>How to determine the true statement</h3>
The function of f(x) is represented as:
![f(x)=x^3-2x^2+4x-8](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E3-2x%5E2%2B4x-8)
Differentiate the function f(x)
![f'(x)=3x^2-4x+4](https://tex.z-dn.net/?f=f%27%28x%29%3D3x%5E2-4x%2B4)
Calculate the minimum value using:
![x = -\frac b{2a}](https://tex.z-dn.net/?f=x%20%3D%20-%5Cfrac%20b%7B2a%7D)
So, we have:
![x = -\frac {-4}{2*3}](https://tex.z-dn.net/?f=x%20%3D%20-%5Cfrac%20%7B-4%7D%7B2%2A3%7D)
![x = \frac {2}{3}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%20%7B2%7D%7B3%7D)
Substitute 2/3 in f'(x)
![f'(2/3)=3*(2/3)^2-4(2/3)+4](https://tex.z-dn.net/?f=f%27%282%2F3%29%3D3%2A%282%2F3%29%5E2-4%282%2F3%29%2B4)
![f'(2/3)=\frac 83](https://tex.z-dn.net/?f=f%27%282%2F3%29%3D%5Cfrac%2083)
The value of f'(2/3) is greater than 0.
This means that the function f(x) has 1 real zero, and it occurs once at point (2,0)
Hence, the true statement is (b)
Read more about functions at:
brainly.com/question/13136492