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3 years ago

Factorize : a. 2tan²A+tanA-6 b. sin²θ.cosθ+sinθ.cos²θ

Mathematics

1 answer:

ollegr [7]3 years ago

6 0

Answer:

Below in bold.

Step-by-step explanation:

a. 2tan²A + tanA - 6

= 2tan²A + 4tanA - 3tanA -6

= 2tanA(tanA + 2) - 3(tanA + 2)

= (2tanA - 3)(tanA + 2)

b. sin²θ.cosθ+sinθ.cos²θ

The GCF is sinθcosθ so the factors are:

sinθcosθ(sinθ + cosθ)

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4 years ago

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brilliants [131]

Answer:

^algebra^

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