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andrew11 [14]
2 years ago
8

Which of the following is a statistical question?

Mathematics
1 answer:
Elena L [17]2 years ago
7 0
C how many students attend natashas school
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What is the value of x in the figure below?
zhenek [66]
Again, nice problem. These are not super easy. You need to imagine the triangles in the figure and relate sides.

For instance: ADC, its hypotenuse is 15

For ABC, it is 20,

so 20/15 is the ratio between both triangles. Now let's choose the side with 'x'

x is one side of ADC, the corresponding side in ABC is 15 (the second longest sides). You need to rotate the triangles, etc ... That's the tricky part :)

So:

20/15 =15/x ----> x = 15*15/20 = 225/20 = 45/4

Which is C

Not sure whether it's too late to help you though!!!!

Also notice that it's kind of a product rule:

x * 20 = 15 * 15

I am sure the book explains a short way of getting to this equation, like sides opposite, blah blah, but what i told you is the reason. You asked for understanding it! Best luck!
7 0
2 years ago
Express 71/1000 as a decimal
tresset_1 [31]

Answer:

71/1000 as a decimal you have to divide numerator by the denominator of the fraction.  

We divide now 71 by 1000 what we write down as 71/1000 and we get 0.071

Step-by-step explanation:


5 0
3 years ago
2) If Michael invests $2000 in the bank at a rate of 5.5% for 6 years how much
Bad White [126]

Answer:

nnn

Step-by-step explanation:

3 0
2 years ago
(3+5i)(3-5i)<br> please show work!
Alexxandr [17]

Answer:

34

Step-by-step explanation:

(3 + 5i)(3 - 5i) = 9 - 25i^2

because i^2 = -1    9 - 25i^2 = 9 - 25x-1 = 34

hope this helped

5 0
2 years ago
Suppose that a password for a computer system must have at least 8, but no more than 12, characters, where each character in the
uranmaximum [27]

Part a)

There are 52 letters (26 lowercase and 26 uppercase), 10 digits, and 6 symbols. There are 52+10+6 = 68 different characters to choose from.

  • If there are 8 characters for this password, then we have 68^8 = 4.5716 * 10^14 different passwords possible.
  • If there are 9 characters, then we have 68^9 = 3.1087 * 10^16 different passwords
  • If there are 10 characters, then we have 68^10 = 2.1139 * 10^18 different passwords
  • If there are 11 characters, then we have 68^11 = 1.4375 * 10^20 different passwords
  • If there are 12 characters, then we have 68^12 = 9.7748 * 10^21 different passwords

Adding up those subtotals gives

68^8+68^9+68^10+68^11+68^12 = 9.9207 * 10^21

different passwords possible.

<h3>Answer: Approximately 9.9207 * 10^21 </h3>

======================================================

Part b)

Let's find the number of passwords where we don't have a special symbol

There are 52+10 = 62 different characters to pick from

  • If there are 8 characters for this password, then we have 62^8 = 2.1834 * 10^14 different passwords possible.
  • If there are 9 characters, then we have 62^9 = 1.3537 * 10^16 different passwords
  • If there are 10 characters, then we have 62^10 = 8.3930 * 10^17 different passwords
  • If there are 11 characters, then we have 62^11 = 5.2037 * 10^19 different passwords
  • If there are 12 characters, then we have 62^12 = 3.2263 * 10^21 different passwords

Adding those subtotals gives

62^8+62^9+62^10+62^11+62^12 = 3.2792 * 10^21

different passwords where we do not have a special character. Subtract this from the answer in part a) above

( 9.9207 * 10^21)  - (3.2792 * 10^21) = 6.6415 * 10^21

which represents the number of passwords where we have one or more character that is a special symbol. I'm using the idea that we either have a password with no symbols, or we have a password with at least one symbol. Adding up those two cases leads to the total number of passwords possible.

<h3>Answer: Approximately 6.6415 * 10^21</h3>

======================================================

Part c)

The answer from part a) was roughly 9.9207 * 10^21

It will take about 9.9207 * 10^21  nanoseconds to try every possible password from part a).

Divide 9.9207 * 10^21  over 1*10^9 to convert to seconds

(9.9207 * 10^21 )/(1*10^9) = 9,920,700,000,000

This number is 9.9 trillion roughly.

It will take about 9.9 trillion seconds to try every password, if you try a password per second.

------

To convert to hours, divide by 3600 and you should get

(9,920,700,000,000)/3600 = 2,755,750,000

So it will take about 2,755,750,000 hours to try all the passwords.

------

Divide by 24 to convert to days

(2,755,750,000)/24= 114,822,916.666667

which rounds to 114,822,917

So it will take roughly 114,822,917 days to try all the passwords.

------

Then divide that over 365 to convert to years

314,583.334246576

which rounds to 314,583

It will take roughly 314,583 years to try all the passwords

------------------------------

<h3>Answers:</h3>
  • 9.9 trillion seconds
  • 2,755,750,000 hours
  • 114,822,917 days
  • 314,583 years

All values are approximate, and are roughly equivalent to one another.

5 0
3 years ago
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