Answer:
see below
Step-by-step explanation:
h(t)=-16t^2+48t+64
Find when h(t) = 64
64 = -16t^2+48t+64
Subtract 64 from each side
0 = -16t^2+48t
Factor
0 = -16t( t-3)
Using the zero product property
-16t =0 t-3 =0
t=0 and t=3
Other than at t=0, so at t=3 seconds
How long will it take for f ball to reach its maximum height?
Find the vertex
t = -b/2a = -48 / ( 2 * -16) = -48/ -32 = 1.5 seconds
It will reach the maximum height at 1.5 seconds
What is the maximum height reached by the ball?
The height will be
h(1.5) = -16*(1.5)^2+48(1.5)+64
= -36+72+64
= 100
The maximum height is 100 ft
How long will it take for the ball to hit the ground?
h(t) =0
0=-16t^2+48t+64
Factor
0 = -16( t^2 - 3t -4)
0=- 16( t-4) (t+1)
Using the zero product property
t-4=0 t+1=0
t =4 t = -1
Since time cannot be negative
t=4 seconds
