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blsea [12.9K]
3 years ago
11

Which expressions can never result in a negative real number when evaluated for any value of x? Select all that apply.

Mathematics
1 answer:
DaniilM [7]3 years ago
8 0
5 whshfunrkfnrj sjdbe
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If the dimensions of the following cylinder are doubled, what factor will the surface area change by?
AVprozaik [17]
To solve this problem you must apply the proccedure shown below:
 1. You have that the radius and the height of the cylinder are:
 r=8 in \\ h=6 in
 2. So, you must calculate the area:
 A1=2 \pi (r+h)
 3. Substitute the values into the formula:
 A1=2 \pi (8 in)(8 in+6in) \\ A1=703.71  in^{2}
 4. When the radius and the height are doubled, you obtain:
 A2=2 \pi (16 in)(16 in+12 in) \\ A2=2814.86 in^{2}
 5. The factor is:
 F=2814.8 in^{2}/703.71  in^{2}  \\ F=4
 The answer is: B. 4

4 0
3 years ago
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Question 1 of 10
yKpoI14uk [10]

Answer:

<5 is the remote interior angle to <1

They are on the same line, or, they are supplementary, and will add up to 180 degrees

5 0
3 years ago
Graph y = 1/2x+3<br> identify the x intercept <br> step by step explanation
lutik1710 [3]

Step-by-step explanation:

x-intercept: where y = 0

Set y to zero to find x.

0 = ½x + 3

-3 = ½x

x = -6

(-6, 0)

7 0
3 years ago
2 Points
mario62 [17]

Answer:

B and E

Step-by-step explanation:

Given the rational expression

\frac{x-7}{2x^2-32} ← factorise the denominator

2x² - 32 ← take out a common factor of 2 from each term

= 2(x² - 16) ← (x² - 16) is a difference of squares

= 2(x - 4)(x + 4)

The expression can now be written as

\frac{x-7}{2(x-4)(x+4)}

The denominator of the expression cannot be zero as this would make the expression undefined. Equating the denominator to zero and solving gives the values that x cannot be.

2(x - 4)(x + 4) = 0

Equate each factor to zero and solve for x

x - 4 = 0 ⇒ x = 4

x + 4 = 0 ⇒ x = - 4

These are the values of x that make the expression undefined.

x = 4 → B

x = - 4 → E

4 0
3 years ago
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If Logan's family can drive 23 1/8 miles on 1 gallon of gas,how far can they drive on 17 gallons
guapka [62]

\bf \begin{array}{ccll} miles&\stackrel{gas}{gallons}\\ \cline{1-2}\\ 23\frac{1}{8}&1\\\\ x&17 \end{array}\implies \cfrac{23\frac{1}{8}}{x}=\cfrac{1}{17}\implies \cfrac{\frac{23\cdot 8+1}{8}}{x}=\cfrac{1}{17}\implies \cfrac{\frac{185}{8}}{x}=\cfrac{1}{17} \\\\\\ \cfrac{\frac{185}{8}}{\frac{x}{1}}=\cfrac{1}{17}\implies \cfrac{185}{8}\cdot \cfrac{1}{x}=\cfrac{1}{17}\implies \cfrac{185}{8x}=\cfrac{1}{17} \\\\\\ 3145=8x\implies \cfrac{3145}{8}=x\implies 393\frac{1}{8}=x

4 0
3 years ago
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