The midpoint of the segment with endpoints (-3,6) and (3, 0) is (0, 3)
<h3>Midpoint of a line </h3>
From the question, we are to determine the midpoint of the segment with the given endpoints
The given endpoints are
(-3,6) and (3, 0)
Given a line with endpoints (x₁, y₁) and (x₂, y₂), then the midpoint of the line is
((x₁+x₂)/2, (y₁+y₂)/2)
Thus,
The midpoint of the line with the endpoints (-3,6) and (3, 0) is
((-3+3)/2, (6+0/2)
= (0/2, 6/2)
= (0, 3)
Hence, the midpoint of the segment with endpoints (-3,6) and (3, 0) is (0, 3)
Learn more on Midpoint of a line here: brainly.com/question/18315903
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3,500 that is the answer to this question because u multiply 7 times 500 and get 3,500
Triangle ABC is equilateral, because AB=BC=AC=a. Then
m∠A=m∠B=m∠C=60°.
Let point D lie on the ray BC to the right from points B and C and let CD=x. Then BD=a+x, AB=a.
Consider triangle ACD. In this triangle, m∠ACD=180°-m∠ACB=180°-60°=120°.
By the cosine theorem,
Since 
then
and
Therefore, you get double inequality
or 
Answer:
http://www.classzone.com/science_book/mls_grade6_FL/540_547.pdf
Step-by-step explanation:
75 1/3 in simplest form: 226/3
