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1 year ago

Find the midpoint of the segment with the following endpoints. (-3,6) and (3, 0)

Mathematics

1 answer:

otez555 [7]1 year ago

3 0

The midpoint of the segment with endpoints (-3,6) and (3, 0) is (0, 3)

<h3>Midpoint of a line </h3>

From the question, we are to determine the midpoint of the segment with the given endpoints

The given endpoints are

(-3,6) and (3, 0)

Given a line with endpoints (x₁, y₁) and (x₂, y₂), then the midpoint of the line is

((x₁+x₂)/2, (y₁+y₂)/2)

Thus,

The midpoint of the line with the endpoints (-3,6) and (3, 0) is

((-3+3)/2, (6+0/2)

= (0/2, 6/2)

= (0, 3)

Hence, the midpoint of the segment with endpoints (-3,6) and (3, 0) is (0, 3)

Learn more on Midpoint of a line here: brainly.com/question/18315903

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Of the students in Mrs. Henderson's class, 3/5 participate in an after school sport. Of these,1/2 play lacrosse. What fraction o

charle [14.2K]

3/5 participate in after school sports...
of these, 1/2 play lacrosse......1/2 of 3/5..." of " means multiply..
1/2 * 3/5 = 3/10....so 3/10 play lacrosse

4 0

3 years ago

Which best describes the graphs of the line that passes through (−12, 15) and (4, −5), and the line that passes through (−8, −9)

konstantin123 [22]

Answer:

C) They are perpendicular lines.

Step-by-step explanation:

We first need to find the slope of the graph of the lines passing through these points using:

$m = \frac{y_2-y_1}{x_2-x_1}$

The slope of the line that passes through (−12, 15) and (4, −5) is

$m_{1} = \frac{ - 5 - 15}{4 - - 12}$

$m_{1} = \frac{ - 20}{16} = - \frac{5}{4}$

The slope of the line going through (−8, −9) and (16, 21) is

$m_{2} = \frac{21 - - 9}{16 - - 8}$

$m_{2} = \frac{21 + 9}{16 + 8}$

$m_{2} = \frac{30}{24} = \frac{5}{4}$

The product of the two slopes is

$m_{1} \times m_{2} = - \frac{4}{5} \times \frac{5}{4} = - 1$

Since

$m_{1} \times m_{2} = - 1$

the two lines are perpendicular.

4 0

3 years ago

Read 2 more answers

Find the value of X so that this quadrilateral is a parallelogram. Then substitute the value of X and using the parallelogram an

Bogdan [553]

Answer:

x = 36

m/A = 132

m/B = 48

m/C = 48

m/D = 132

4 0

3 years ago

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

2 years ago

4x-5=7+4y<br> How do you solve?

solong [7]

solve for x.

4x−5=7+4y

Add 5 to both sides.

4x−5+5=4y+7+5

4x=4y+12

Divide both sides by 4.

4x/4=4y+12/4

x=y+3

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Have a nice day! :)

5 0

3 years ago