Can someone please solve this

A farmer has 50 acres of corn crops. He harvested 3 acres of his crops in one afternoon. What is the decimal that represents the

kakasveta [241]

The decimal that represents the amount he harvested, is 0.06 because 3/50 is equivalent to 0.06 acres of corn crops.

3 0

3 years ago

PART 1!! There’s more to it so please help me!! lesson 3.3.4 Practice: modeling: graphs of functions!

asambeis [7]

Answer:

the first cell next to 3 (time hours x) is 300

the point is (3, 300)

the second cell is 1000

the point is (10,1000)

the values for the second table should be the same if they have the same unit rate which is 100 watts per hour

Step-by-step explanation:

If there is 100 watts perhour just multiply the number of hours by this unit

5 0

3 years ago

Suppose that the speed at which cars go on the freeway is normally distributed with mean 68 mph and standard deviation 5 miles p

denis23 [38]

Answer:

A) $X \sim N(68 , 25)$

B) the probability that is traveling more than 70 mph is 0.3446

C) the probability that it is traveling between 65 and 75 mph is 0.6449

D) 90% of all cars travel at least 56.85 mph fast on the freeway

Step-by-step explanation:

The speed at which cars go on the freeway is normally distributed with mean 68 mph and standard deviation 5 miles per hour.

Mean = $\mu = 68 mph$

Standard deviation = $\sigma = 5 mph$

A) X ~ N( _____, _______ )

In general $X \sim N( \mu , \sigma^2)$

$\mu = 68 mph$

$\sigma = 5 mph$

$\sigma^2 = 5^2 = 25$

So, $X \sim N(68 , 25)$

B) If one car is randomly chosen, find the probability that is traveling more than 70 mph.i.e.P(X>70)

So, $Z = \frac{x-\mu}{\sigma}\\Z=\frac{70-68}{5}$

Z=0.4

Using Z table

P(Z>70)=1-P(Z<70)=1-0.6554=0.3446

Hence the probability that is traveling more than 70 mph is 0.3446

C) If one of the cars is randomly chosen, find the probability that it is traveling between 65 and 75 mph.

P(65<X<75)

$Z = \frac{x-\mu}{\sigma}$

AT x = 65

$Z=\frac{65-68}{5}$

Z=-0.6

AT x = 75

$Z=\frac{75-68}{5}$

Z=1.4

Using Z table

P(65<X<75)=P(-0.6<Z<1.4)=P(Z<1.4)-P(Z<-0.6)=0.9192-0.2743=0.6449

Hence the probability that it is traveling between 65 and 75 mph is 0.6449

D)90% of all cars travel at least how fast on the freeway?

Since we are supposed to find at least how fast on the freeway

So,P(X>x)=0.9

1-P(X<x)=0.9

1-0.9=P(X<x)

0.1=P(X<x)

Z value at 10% =-2.23

So, $Z=\frac{x-\mu}{\sigma}\\-2.23=\frac{x-68}{5}\\-2.23 \times 5 =x-68\\(-2.23 \times 5)+68=x$

56.85 = x

Hence 90% of all cars travel at least 56.85 mph fast on the freeway

8 0

3 years ago

Jason can travel 24 3/4 miles in one half hour what is his average speed in miles per hour

BARSIC [14]

Average speed = 24 3/4 / 1 1/2 = 99/4 / 3/2 = 99/4 x 2/3 = 16 1/2 miles per hour.

3 0

3 years ago

Read 2 more answers

Michael hires a cab that charges a fare of $0.50 per mile, plus an initial charge of $2. Jason hires a cab that charges a fare o

Vanyuwa [196]

use reapeted addition and keep adding +$0.50 until you get $4.00 for it to be equal with Jason's total which was $4.00

so it will be at 3 miles.

or just multiply micheals total by 3.:) hope it helped!!

8 0

4 years ago