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Veronika [31]
3 years ago
12

Which sets of values belong to the domain and range of a relation

Mathematics
1 answer:
Ann [662]3 years ago
5 0

Answer:

Domain are the INDEPENDANT , INPUT values

Range are the DEPENDANT , OUTPUT values

Step-by-step explanation:

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All the pencils have the same width. How wide is each pencil? (the struggle is real lemme just say)
USPshnik [31]

Answer:

2 centimeters wide? I-

Step-by-step explanation:

7 0
3 years ago
A college-entrance exam is designed so that scores are normally distributed with a mean of 500 and a standard deviation of 100.
Crank

Answer: 1.25

Step-by-step explanation:

Given: A college-entrance exam is designed so that scores are normally distributed with a mean(\mu) = 500 and a standard deviation(\sigma) =  100.

A z-score measures how many standard deviations a given measurement deviates from the mean.

Let Y be a random variable that denotes the scores in the exam.

Formula for z-score = \dfrac{Y-\mu}{\sigma}

Z-score = \dfrac{625-500}{100}

⇒ Z-score = \dfrac{125}{100}

⇒Z-score =1.25

Therefore , the required z-score = 1.25

6 0
3 years ago
What times what equals 84
Kisachek [45]
42 times 2 because 84 divided by 24 equals 2. Also, 84 divided by 2 equals 24.
8 0
3 years ago
Read 2 more answers
Assume that k and V0 are constant and are, respectively, 0.02, and 7. The parameter CA varies from an initial value CA0 = 100 to
julia-pushkina [17]

Answer:

V = 929.7

Step-by-step explanation:

Given the equation:

\frac{dCA}{dV} = \frac{-kCA}{V0}

The integral of the above equation is:

\int\limits {\frac{dCA}{dV} } = \int\limits{\frac{-kCA}{V0} }

Re-organizing the integrals:

\int\limits  {\frac{dCA}{CA} } = \int\limits {\frac{-kdV}{V0} }

Integrating:

ln(CA) - ln(CA0) = \frac{-kV}{V0}

Inputting the initial conditions of CA and the values of k and V0:

ln(7) - ln(100) = \frac{-0.02V}{7}

1.946 - 4.605 = -0.00286V

-2.659 = -0.00286V

=> V = \frac{2.659}{0.00286}

V = 929.720

Approximating to one decimal place,

V = 929.7

7 0
3 years ago
PLEASER HELP!! 40 POINTS
Reika [66]
Hope this helps! i hope you’re having a good day

5 0
3 years ago
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