Answer:
-7
Step-by-step explanation:
We first are going to flip the equation around.
So instead of 9 times x = -36 we'll do 36/9. 36/9 = -7.
Also you will kind of know it will be a negative number from the beginning since it's -36.
I don't know if that last part makes any sense, but I hope this helps you!
Foil the right side. Multiply first, outer, inter, and the last terms. The right side is equal to x^2 + 11x + 18x. N is 11.
Answer:
2345 units^2
Step-by-step explanation:
First, you can use Soh Cah Toa to find line c to be 36*sqrt(2). Furthermore, you can use the same equation to find the other sides to be both 65.15. To further solve, you just need to multiply 65.15 by 36 to get a final answer of 2,345.4 units^2
<em>Please Mark Brainliest if this helped!</em>
Answer:
The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.
The function to represent the mass of the sample after t days is ![A(t) = 810(0.74)^t](https://tex.z-dn.net/?f=A%28t%29%20%3D%20810%280.74%29%5Et)
Step-by-step explanation:
Exponential equation of decay:
The exponential equation for the amount of a substance is given by:
![A(t) = A(0)(1-r)^t](https://tex.z-dn.net/?f=A%28t%29%20%3D%20A%280%29%281-r%29%5Et)
In which A(0) is the initial amount and r is the decay rate, as a decimal.
Hourly rate of change:
Decreases 26% by day. A day has 24 hours. This means that
; We use this to find r.
![A(t) = A(0)(1-r)^t](https://tex.z-dn.net/?f=A%28t%29%20%3D%20A%280%29%281-r%29%5Et)
![0.74A(0) = A(0)(1-r)^{24}](https://tex.z-dn.net/?f=0.74A%280%29%20%3D%20A%280%29%281-r%29%5E%7B24%7D)
![(1-r)^{24} = 0.74](https://tex.z-dn.net/?f=%281-r%29%5E%7B24%7D%20%3D%200.74)
![\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}](https://tex.z-dn.net/?f=%5Csqrt%5B24%5D%7B%281-r%29%5E%7B24%7D%7D%20%3D%20%5Csqrt%5B24%5D%7B0.74%7D)
![1 - r = (0.74)^{\frac{1}{24}}](https://tex.z-dn.net/?f=1%20-%20r%20%3D%20%280.74%29%5E%7B%5Cfrac%7B1%7D%7B24%7D%7D)
![1 - r = 0.9875](https://tex.z-dn.net/?f=1%20-%20r%20%3D%200.9875)
![r = 1 - 0.9875 = 0.0125](https://tex.z-dn.net/?f=r%20%3D%201%20-%200.9875%20%3D%200.0125)
The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.
Starts out with 810 grams of Element X
This means that ![A(0) = 810](https://tex.z-dn.net/?f=A%280%29%20%3D%20810)
Element X is a radioactive isotope such that its mass decreases by 26% every day.
This means that we use, for this equation, r = 0.26.
The equation is:
![A(t) = A(0)(1-r)^t](https://tex.z-dn.net/?f=A%28t%29%20%3D%20A%280%29%281-r%29%5Et)
![A(t) = 810(1 - 0.26)^t](https://tex.z-dn.net/?f=A%28t%29%20%3D%20810%281%20-%200.26%29%5Et)
![A(t) = 810(0.74)^t](https://tex.z-dn.net/?f=A%28t%29%20%3D%20810%280.74%29%5Et)
The function to represent the mass of the sample after t days is ![A(t) = 810(0.74)^t](https://tex.z-dn.net/?f=A%28t%29%20%3D%20810%280.74%29%5Et)
Answer:
I think 1 is negative, 2 undefined, 3 negative, 4 positive
Step-by-step explanation: