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a_sh-v [17]
3 years ago
13

Factor each trinomial. Then match the polynomial (term) on the left with its factored form (definition) on the right.

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
7 0
<span>x2 – 4x – 12 A) (x – 6)(x + 2) x2 + 4x – 12 B) Prime x2 – x – 12 C) (x – 4)(x + 3) x2 – 7x – 12 D) (x – 2)(x + 6) i think this is the awnser:)</span>
Nuetrik [128]3 years ago
5 0
<h2>Answer:</h2>

x^2-4x-12\ ------------------\ (x+2)(x-6)\\\\x^2+4x-12\ -----------------\ (x-2)(x+6)\\\\x^2-x-12\ -------------------\ (x-4)(x+3)\\\\x^2-7x-12\ ------------------\ Prime

<h2>Step-by-step explanation:</h2>

1)

x^2-4x-12

This could be factored by using the method of splitting the middle term.

i.e.

x^2-4x-12=x^2-6x+2x-12\\\\i.e.\\\\x^2-4x-12=x(x-6)+2(x-6)\\\\i.e.\\\\x^2-4x-12=(x+2)(x-6)

2)

x^2+4x-12

This could again be factored by the method of splitting the middle term as follows:

x^2+4x-12=x^2+6x-2x-12\\\\i.e.\\\\x^2+4x-12=x(x+6)-2(x+6)\\\\i.e.\\\\x^2+4x-12=(x-2)(x+6)

3)

x^2-x-12

This could be factored by using the method of splitting the middle term.

i.e.

x^2-x-12=x^2-4x+3x-12\\\\i.e.\\\\x^2-x-12=x(x-4)+3(x-4)\\\\i.e.\\\\x^2-x-12=(x-4)(x+3)

4)

x^2-7x-12

This polynomial could not be factored.

Hence, it is a prime expression.

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Step-by-step explanation:


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